How heavy a load, in pounds, is needed to pull apart pieces of Douglas fir 44 in. long and 1.51.5 in. wide with a standard deviation ?σ of 30003000 lbs? Estimate the mean load ?μ needed to pull apart the pieces of wood to within plus or minus 600600 lbs with 95%95% confidence. Determine how large of a sample size ?n is needed. You might find a table of ?-z-critical values useful. n=

Q: The average weight of an elephant is 6.42 tons with a standard deviation of 1.07 tons. Use the…

A: Given Mean=6.42 Standard deviation = 1.07 By Empirical rule

Q: The mean height for the population of a species of gorilla is believed to be 70 inches, and the…

A: Sample size n =20 Sample mean=73 Population standard deviation =4 NOTE:- According to bartleby…

Q: For a population with u = 34, a score of X = 31 corresponds to z = -1.00. The standard deviation for…

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Q: The pulse rates of 167 randomly selected adult males vary from a low of 39 bpm to a high of 119 bpm.…

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Q: In order to infer on the mean height of children in a school , a sample of 36 students were…

A: Obtain the standard error for the sample mean. The standard error for the sample mean is obtained…

Q: Assuming that a sample is used to estimate a population mean μμ. Find the margin of error M.E. that…

A: From the provided information, Sample size (n) = 22 Sample mean (x̅) = 16.7 Sample standard…

Q: How heavy a load, in pounds, is needed to pull apart pieces of Douglas fir 4 in. long and 1.5in.…

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Q: If you want to be 99​% confident of estimating the population proportion to within a sampling error…

A: compute sample size ( n ) = n=(Z/E)^2*p*(1-p)

Q: We want to obtain a sample to estimate a population mean. Based on previous evidence, researchers…

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Q: 49 scores with M = 43 is selected from a population with µ = 40 with σ = 21. What is the standard…

A: Here it is given that- Total number of sample (n) = 49 Sample mean (M) = 43 Population mean (μ) = 40…

Q: Independent-samples t-test. A psychologist studied the nature of sounds generated during eating.…

A: (a) The null and alternative hypothesis is given by; μ1=Mean of peak loudness with open mouthμ2=Mean…

Q: A randam sample of 20 apartments has a mean of AED 4000 and a standard error (a/(vn)) of 1,000. You…

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Q: The pulse rates of 142 randomly selected adult males vary from a low of 37 bpm to a high of 101 bpm.…

A: E = 4 bpm Confidence interval = 90%

Q: The pulse rates of 175 randomly selected adult males vary from a low of 41 bpm to a high of 109 bpm.…

A: Given,  Max = 109 Min = 41 E = 3

Q: We would like to estimate the mean amount a shopper spends during a visit to the local supermarket.…

A: 90% confidence interval for meanMargin of error : E = 2.50Population standard deviation : Required…

Q: MSC 600 Quantitative Methods 7. Part of an ANOVA table is shown below. Source of Variation Between…

A: dftreatment=3 , SStreatment=180 , dftotal=18 SStotal=480

Q: We want to obtain a sample to estimate a population mean. Based on previous evidence, researchers…

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Q: Random samples of two species of iris gave the following petal lengths (in cm). x1, Iris virginica…

A: Given data provides random samples of two species of iris gave the following petal lengths (in cm).…

Q: average heigth is 163 cm, standart deviation is 10 cm. compute p(X>168 cm) ?

A: Given,μ=163σ=10P(X>168)=?

Q: Juan wants to estimate a population mean age of residents of a retirement community. Based on…

A: Obtain the sample size needed. The sample size needed is obtained below as follows : Obtain the…

Q: 3. A sample of 26 pieces of data is collected and we wish to perform the a=.05 level test Ho:u=6 vs.…

A: Given , Hypothesis : H0 : μ= 6 H1 : μ> 6 Right tailed test. Test statistic = z = 1.61

Q: During rush hour, the traffic speed on a busy highway is found to have mean 42 mph and standard…

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Q: SEM for a sample of size 100 and standard deviation of 5.6 is equal to?   a  14/25   b 23/100   c…

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Q: The diameter of a spindle in a small motor pool is supposed to be 5 millimeters.  If the spindle is…

A: We have given that  Sample size n=225 , xbar=4.89 and mu=5

Q: Q2.Humorous bones from the same species of animal have approximately the same length-to-width…

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Q: Polymer composite materials have gained popularity because they have high strength to weight ratios…

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Q: The pulse rates of 154 randomly selected adult males vary from a low of 45 bpm to a high of 121 bpm.…

A: given data, CI=0.99E=4α=1-0.99=0.01Zc=Zα/2    =Z0.01/2    =Z0.0050    =2.576 [from excel function,…

Q: A model fit predicting preference for President (Democrat, Republican, Independent) using x = annual…

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Q: A population has mean u = 30 and standard deviation O = 21. Find U- and 0- for samples of size n =…

A: We have to find given probability..

Q: The pulse rates of 157 randomly selected adult males vary from a low of 44 bpm to a high of 112 bpm.…

A: Given that: Pulse rates of 157 adult males vary from 44 bpm to 112 bpm. Sample mean 'm' lies between…

Q: An article reports that men over 6 ft tall earn more than men under 6ft . with these numbers:…

A: From the provided information, The hypotheses for this test can be constructed as: H0: µ1 = µ2 H1:…

Q: The pulse rates of 172 randomly selected adult males vary from a low of 41 bpm to a high of 105 bpm.…

A:

Q: The pulse rates of 155 randomly selected adult males vary from a low of 35 bpm to a high of 99 bpm.…

A: The sample size is .The minimum value of sample data is  bpm. The maximum value of sample data is 99…

Q: Consider a normal population with µ = 50 and σ = 6. A sample size of at least which size needs to be…

A: The population standard deviation is 6 and margin of error is 2 or less.

Q: A sample of n = 64 scores is selected from a population with µ = 80 and with σ = 24. On average, how…

A: Given A sample of n = 64 scores is selected from a population with µ = 80 and with σ = 24. On…

Q: The pulse rates of 164 randomly selected adult males vary from a low of 45 bpm to a high of 105 bpm.…

A: Confidence level = 98 % Error,E = 2 Lowest pulse rate = 45 highest pulse rate = 105 Zcric = 2.33

Q: The lengths of pregnancies in a small rural village are normally distributed with a mean od 262 days…

A: Given info: The lengths of pregnancies (x) is normally distributed with mean 262 days and standard…

Q: The pulse rates of 164 randomly selected adult males vary from a low of 41 bpm to a high of 121 bpm.…

A: Given The data is as follows: Sample size, n=164 Confidence level, CL=0.99 Margin of error, E=4

Q: Compute for the sample size if the margin of error is 15, with a sample standard deviation of 55 and…

A: We have given that the margin of error is 15, with a sample standard deviation of 55 and a 95% level…

Q: State the conclusion based on the results of the test. The mean of the pressure required to open a…

A: The mean of the pressure required to open a certain valve is known to be = 7.9 psi. H0 :  P =  7.9…

Q: The pulse rates of 159 randomly selected adult males vary from a low of 38 bpm to a high of 106 bpm.…

A: GivenConfidence Interval(c)=90%Margin of error(E)=3pulse rates vary from 38 bpm to high 106bpm

Q: The amount of trash generated by US households (in lbs per day) is normally distributed. You take a…

A: Sample mean = x̅ = 10.91 Sample size = n = 10 Sample S.D = s = 4.736 Standard Error = s/√n  =…

Q: Q.3 Assume that the heights of men are normally distributed with a standard deviation of 2.5 inches.…

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Q: What sample size is needed to give a margin of error within ±0.8 in estimating a population mean…

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Q: he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 111 bpm.…

A: a. The standard deviation is calculated as: s=max-min4=111-434=17 At 95% confidence level, the z…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.