How does the magnitude of the kinetic frictional force on an object depend on the normal force on the object? How do you determine the value of the coefficient of kinetic friction from a kinetic frictional force vs normal force graph? What role does the kinetic frictional force play as a crate slides down a ramp? How could you change the angle of the ramp to your advantage as you unload the props?
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How does the magnitude of the kinetic frictional force on an object depend on the normal force on the object?
How do you determine the value of the coefficient of kinetic friction from a kinetic frictional force vs normal force graph?
What role does the kinetic frictional force play as a crate slides down a ramp? How could you change the angle of the ramp to your advantage as you unload the props?
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- A small box of mass m1 is sitting on a board of mass m2 and length L. The coefficient of kinetic friction between the board and the horizontal floor is μk . The coefficient of static friction between the board and the box is μs.At this moment, the board slides to the right along the surface, while the box does not slide on the board. What is the maximum magnitude of the force F pulling the board so that the box does not slip on the board? * the answer key is (Us+Uk)(m1+m2)g, I don't know how to get here.MehulyoGOAL Apply the concept of static friction to an object resting on an incline. PROBLEM Suppose a block with a mass of 2.50 kg is resting on a ramp. If the coefficient of static friction between the block and ramp is ng sin e 0.350, what maximum angle can the ramp make with the horizontal mg cos e e before the block starts to slip down? STRATEGY This is an application of Newton's second law involving an object in equilibrium. Choose tilted coordinates, as in the figure. Use the fact that the block is just about to slip when the force of static friction takes its maximum value, f. = 4n. SOLUTION Write Newton's laws for a static system (1) EF = mg sin e - u̟n = 0 in component form. The gravity force (2) EF = n - mg cos e = 0 has two components. Rearrange Equation (2) to get an n = mg cos 8 expression for the normal force n. Substitute the expression for n into EF, = mg sin 8 - H mgcos 0 = 0 → tan 8 =u. Equation (1) and solve for tan 0. Apply the inverse tangent function to get the answer.…
- A car with a mass of 922 kg rounds the top of the hill at a speed of 10 m/s. The friction between the wheels and the road is negligible and the radius of curvature for the hill is 32 m. A. Draw the force diagram and write down a Newton’s 2nd law equation for the car when it is at the top of the hill. B. Find the magnitude of the normal force on the car when it rounds the hill at this speed. C. What is the maximum speed at which the car could round this hill without losing contact with the road?A 40 N box is resting on a table when a 20 N force is applied to it horizontally. The coefficients of static and kinetic friction are 0.3 and 0.1, respectively. Which of the following best describes the resulting motion of the box? The motion of the box cannot be determined with the given information. The box accelerates in the direction of the applied force. The box remains at rest. The box moves with a constant velocity in the direction of the applied force.Questions 5 and 6 refer to the diagram below. m A box of mass m is being pushed up a ramp by a force F acting along the ramp, as shown. The ramp makes an angle to the horizontal, and the coefficient of kinetic friction between the box and the ramp is μ. The normal force and the frictional force exerted on the box are F and f, respectively. 5. Which of the following free-body diagrams correctly shows the forces exerted on the box as it moves up the ramp? (A) (E) FN F F mg mg mg (B) A ohibitedRprint F FN mg Unauthorized copying or reuse of any part of this page is illegal. -8- GO ON TO TI 6. If the force F has a magnitude of 2mg, which of the following is a correct expression for the acceleration of the box? (A) g sine (B) 2g (C) 8 (D) (2-cos@)g (E) g(2 sine cose) - -
- Current Attempt in Progress A 18-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 22 N. Starting from rest, the sled attains a speed of 2.5 m/s in 9.2 m. Find the coefficient of kinetic friction between the runners of the sled and the snow. Number i eTextbook and Media GO Tutorial Save for Later Units Attempts: 0 of 4 used Submit AnswerIdentify the correct answer and explain the answer Why is the answer choice chosen wrong?A cannonball has just been shot out of a cannon aimed 45∘ above the horizontal rightward direction. Drag forces cannot be neglected.Which way does drag point? I thought it points opposite of the direction of the motion.
- helpv Question Completion Status: QUESTION 18 As shown in the figure below, a force pushes two mass bodies (mass m, and m) together moving to right horizontally with a constant acceleration on a frictionless and as shown above. With E=10 N, m, = 11 kg, and m,= 13 kg, what is the surface, In the contact surface between m, and m., there are contacting forces E 21 magnitude of F, N Please write your numerical answer with all digits and do not use (Note: For fill in blank, I have set the unit for the answer. So, you just need to provide a number scientific notation. If you are not sure about the number of significant figures, you can keep the number of figures as many as possible - You will not be punished for doing this.) F21 m1 Click Save and Submit to save and submit. Click Save All Answers to save all answers. Type here to search