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How does someone Draw this Chemical Equation? I would like to draw a picture  This was the information given by ChatGBT and it wasn't helpful to me so wondering if someone would be able to help draw a picture: The chemical equation for the oxidation of benzoin to benzil using sodium hypochlorite as the oxidizing agent can be represented as follows: (CHECK PICTURE SENT) This equation shows the conversion of benzoin (C14H12O2) to benzil (C14H10O2) in the presence of sodium hypochlorite (NaOCl), resulting in the formation of sodium hydroxide (NaOH) and water (H2O) as by-products.

How does someone Draw this Chemical Equation? I would like to draw a picture  This was the information given by ChatGBT and it wasn't helpful to me so wondering if someone would be able to help draw a picture: The chemical equation for the oxidation of benzoin to benzil using sodium hypochlorite as the oxidizing agent can be represented as follows: (CHECK PICTURE SENT) This equation shows the conversion of benzoin (C14H12O2) to benzil (C14H10O2) in the presence of sodium hypochlorite (NaOCl), resulting in the formation of sodium hydroxide (NaOH) and water (H2O) as by-products.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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PLEASE READ EVERYTHING SENT... I keep getting questions Half done because there is no patience  to read it all. 
How does someone Draw this Chemical Equation? I would like to draw a picture 
This was the information given by ChatGBT and it wasn't helpful to me so wondering if someone would be able to help draw a picture:
The chemical equation for the oxidation of benzoin to benzil using sodium hypochlorite as the oxidizing agent can be represented as follows: (CHECK PICTURE SENT)
This equation shows the conversion of benzoin (C14H12O2) to benzil (C14H10O2) in the presence of sodium hypochlorite (NaOCl), resulting in the formation of sodium hydroxide (NaOH) and water (H2O) as by-products.

2 C14H12O2 + NaOCl → 2 C14H10O2 + NaOH + H₂O
Transcribed Image Text:2 C14H12O2 + NaOCl → 2 C14H10O2 + NaOH + H₂O
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