How do you solve for part 4 One mole of iron (6 1023 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 10-10 m. You have a long thin bar of iron, 2.5 m long, with a square cross section, 0.05 cm on a side.You hang the rod vertically and attach a 29 kg mass to the bottom, and you observe that the bar becomes 1.42 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.ks = 20014.1 N/mNumber of side-by-side long chains of atoms = 4.81e12Number of bonds in total length = 1.096e104) What is the stiffness of a single interatomic "spring"?
How do you solve for part 4 One mole of iron (6 1023 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 10-10 m. You have a long thin bar of iron, 2.5 m long, with a square cross section, 0.05 cm on a side.You hang the rod vertically and attach a 29 kg mass to the bottom, and you observe that the bar becomes 1.42 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.ks = 20014.1 N/mNumber of side-by-side long chains of atoms = 4.81e12Number of bonds in total length = 1.096e104) What is the stiffness of a single interatomic "spring"?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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How do you solve for part 4
One mole of iron (6 1023 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 10-10 m. You have a long thin bar of iron, 2.5 m long, with a square cross section, 0.05 cm on a side.
You hang the rod vertically and attach a 29 kg mass to the bottom, and you observe that the bar becomes 1.42 cm longer. From these measurements, it is possible to determine the stiffness of one interatomic bond in iron.
ks = 20014.1 N/m
Number of side-by-side long chains of atoms = 4.81e12
Number of bonds in total length = 1.096e10
4) What is the stiffness of a single interatomic "spring"?
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