How do you find moles for samples of different unknown gases if only the pressure (in atm) is given?  Three containers A,B,C have three samples of different gases. A has 1.52 atm B has 0.456 atm C has 0.93 atm Total pressure if all three were transferred to another container = 2.91 atm   My question is I need to find the mole fraction of each gas but I need to find the moles of each gas first but the only information given is the pressures.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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How do you find moles for samples of different unknown gases if only the pressure (in atm) is given? 

Three containers A,B,C have three samples of different gases.

A has 1.52 atm

B has 0.456 atm

C has 0.93 atm

Total pressure if all three were transferred to another container = 2.91 atm

 

My question is I need to find the mole fraction of each gas but I need to find the moles of each gas first but the only information given is the pressures. 

Expert Solution
Step 1 To calculate

Given, a mixture of gas A,B and C having pressure 1.52 atm, 0.456 atmand 0.93 atm respectively.and the total pressure of mixture of the gas is 2.91 atm.we are asked to calculate the mole fraction of each gas present inmixture.

Step 2 Formula used and Calculation

The mole fraction of each gas can  be obtained from Dalton's law of partial pressure for gases, according to which,Partial pressure of gas =mole fraction of gas ×Total pressure of gasThus, mole fraction of gas A,B and C are as follow,mole fraction of gas A (χA)=partial pressure of gas ATotal pressure of gas mixturemole fraction of gas A (χA) =1.52 atm2.91 atm =0.52 mole fraction of gas B (χB)=partial pressure of gas BTotal pressure of gas mixturemole fraction of gas B (χB) =0.456 atm2.91 atm =0.16mole fraction of gas C (χC)=partial pressure of gas CTotal pressure of gas mixturemole fraction of gas C (χC) =0.93 atm2.91 atm=0.32Thus, the mole fraction of gas A,B and C are 0.52, 0.16 and 0.32 respectively.

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