How do you derermine of RS → R* 76 onto?

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Linear Algebra.

**Understanding Onto Transformations:**

The text poses a question about linear transformations:

**"How do you determine if \( \mathbb{R}^3 \rightarrow \mathbb{R}^4 \) is onto?"**

### Explanation:

In linear algebra, a transformation (or function) from one vector space to another is called *onto* or *surjective* if every element in the second space is mapped to by some element from the first space. In this case, the transformation is from \(\mathbb{R}^3\) to \(\mathbb{R}^4\). 

To determine if this transformation is onto, you can consider the following:

1. **Rank of the Matrix:** For a linear transformation to be onto, the rank of its corresponding matrix must be equal to the dimension of the codomain (\(\mathbb{R}^4\) in this case). This means that the matrix must have full row rank, but since \(\mathbb{R}^3\) has only 3 dimensions and \(\mathbb{R}^4\) has 4, it's impossible for a linear transformation from \(\mathbb{R}^3\) to \(\mathbb{R}^4\) to be onto. 

2. **General Rule:** In general, a transformation \(\mathbb{R}^m \rightarrow \mathbb{R}^n\) can only be onto if \(m \geq n\).

Thus, a function from \(\mathbb{R}^3\) to \(\mathbb{R}^4\) cannot be onto, as the number of dimensions in the domain is less than in the codomain.
Transcribed Image Text:**Understanding Onto Transformations:** The text poses a question about linear transformations: **"How do you determine if \( \mathbb{R}^3 \rightarrow \mathbb{R}^4 \) is onto?"** ### Explanation: In linear algebra, a transformation (or function) from one vector space to another is called *onto* or *surjective* if every element in the second space is mapped to by some element from the first space. In this case, the transformation is from \(\mathbb{R}^3\) to \(\mathbb{R}^4\). To determine if this transformation is onto, you can consider the following: 1. **Rank of the Matrix:** For a linear transformation to be onto, the rank of its corresponding matrix must be equal to the dimension of the codomain (\(\mathbb{R}^4\) in this case). This means that the matrix must have full row rank, but since \(\mathbb{R}^3\) has only 3 dimensions and \(\mathbb{R}^4\) has 4, it's impossible for a linear transformation from \(\mathbb{R}^3\) to \(\mathbb{R}^4\) to be onto. 2. **General Rule:** In general, a transformation \(\mathbb{R}^m \rightarrow \mathbb{R}^n\) can only be onto if \(m \geq n\). Thus, a function from \(\mathbb{R}^3\) to \(\mathbb{R}^4\) cannot be onto, as the number of dimensions in the domain is less than in the codomain.
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