How do triphenylphosphine and borane form a Lewis acid-base adduct? (a) The phosphorus atom in triphenylphosphine is less electronegative than the boron atom in borane and is thus attracted to boron to form the bond. (b) The phosphorus in triphenylphosphine exchanges with the boron from borane. (c) Triphenylphosphine donates the lone pair on its phosphorus to the electron-deficient boron in borane. (d) Triphenylphosphine donates a phenyl ring from its phosphorus to the electron-deficient boron in borane. (e) The phosphorus in triphenylphosphine accepts a proton from the proton-rich borane.

How do triphenylphosphine and borane form a Lewis acid-base adduct? (a) The phosphorus atom in triphenylphosphine is less electronegative than the boron atom in borane and is thus attracted to boron to form the bond. (b) The phosphorus in triphenylphosphine exchanges with the boron from borane. (c) Triphenylphosphine donates the lone pair on its phosphorus to the electron-deficient boron in borane. (d) Triphenylphosphine donates a phenyl ring from its phosphorus to the electron-deficient boron in borane. (e) The phosphorus in triphenylphosphine accepts a proton from the proton-rich borane.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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