how do they determine k
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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this is a text book example NOT for grading, how do they determine k
![Torsional natural frequency
4₁ = 600 m
d₁ = 80mm
G = 80GPa
J₁ = 900kgm²
1₂ = 800 m
d₂ = 60mm
G = 80GPa
J₂ = 400kgm²
k₁0₁
www
J₁
J₂
K₁1
K12
4010
K₁2(02-0₁)
02
Equation of motion for J₁:
kt101 + kt201 - kt20₂ + J₁0₁ = 0
(kt1+kt2)01(kt2)02-J₁w²0₁ = 0
Equation of motion for J₂:
Kt202 - Kt201 +J₂0₂ = 0
-(kt2) 01 + (kt2)02-J₂w²0₂ = 0
Equations of motion in matrix form:
[(ker
+ Kt2-J₁w²)
(-ktz)
0 (t) = Osin(wt)
ä(t) = -w²0sin(wt)
=
(K²₂-12²)][82] [81](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa36211ff-413d-45db-8330-03ac493e19cc%2Fe2f68d97-cfb2-4be2-9b70-b984385b16dd%2F8k5aj5n_processed.png&w=3840&q=75)
Transcribed Image Text:Torsional natural frequency
4₁ = 600 m
d₁ = 80mm
G = 80GPa
J₁ = 900kgm²
1₂ = 800 m
d₂ = 60mm
G = 80GPa
J₂ = 400kgm²
k₁0₁
www
J₁
J₂
K₁1
K12
4010
K₁2(02-0₁)
02
Equation of motion for J₁:
kt101 + kt201 - kt20₂ + J₁0₁ = 0
(kt1+kt2)01(kt2)02-J₁w²0₁ = 0
Equation of motion for J₂:
Kt202 - Kt201 +J₂0₂ = 0
-(kt2) 01 + (kt2)02-J₂w²0₂ = 0
Equations of motion in matrix form:
[(ker
+ Kt2-J₁w²)
(-ktz)
0 (t) = Osin(wt)
ä(t) = -w²0sin(wt)
=
(K²₂-12²)][82] [81

Transcribed Image Text:Torsional natural frequency
J₁
J₂
K₁1
K12
01
0₂
Calculate the natural frequencies:
(ke1 + Ktz-J₁w²)
(-Ktz)
(-ktz)
(ktz~1/26²) = 0
360000w4379870910w² +68218704777.675003 = 0
Wn1 = 28,73 rad/s
fn1 = 4,57Hz
Wn2 = 15,15 rad/s
fn2 = 2,41Hz
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