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How do I solve for the percentage of error of the experiment?  Data table:  mass of empty 8'' test tube: 41.47 mass of test tube and metal: 91.59 the initial temperature of metal: 10.5 degrees Celcius  mass of water in a cup: 75g  the initial temperature of water: 24.7 degrees Celcius  the final temperature of metal and water mix: 34.2 degrees celsius  specific heat of water: 4.184 j/g degrees celsius  specific heat of metal: 15.8 j/g celsius

How do I solve for the percentage of error of the experiment?  Data table:  mass of empty 8'' test tube: 41.47 mass of test tube and metal: 91.59 the initial temperature of metal: 10.5 degrees Celcius  mass of water in a cup: 75g  the initial temperature of water: 24.7 degrees Celcius  the final temperature of metal and water mix: 34.2 degrees celsius  specific heat of water: 4.184 j/g degrees celsius  specific heat of metal: 15.8 j/g celsius

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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How do I solve for the percentage of error of the experiment? 

Data table: 

mass of empty 8'' test tube: 41.47

mass of test tube and metal: 91.59

the initial temperature of metal: 10.5 degrees Celcius 

mass of water in a cup: 75g 

the initial temperature of water: 24.7 degrees Celcius 

the final temperature of metal and water mix: 34.2 degrees celsius 

specific heat of water: 4.184 j/g degrees celsius 

specific heat of metal: 15.8 j/g celsius 

Expert Solution
Step 1

Given,

mass of empty 8'' test tube= 41.47g

mass of test tube and metal= 91.59 g

Therefore mass of metal=(91.59-41.47)=50.12 g

Initial temperature of metal=10.5°C

Final temperature of metal and water mix=34.2°C

Mass of water=75g

initial temperature of water=24.7°C

Specific heat of water=4.184 J/g°C

Specific heat of metal (given)=15.8J/g°C

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