How do I solve for the percentage of error of the experiment? Data table: mass of empty 8'' test tube: 41.47 mass of test tube and metal: 91.59 the initial temperature of metal: 10.5 degrees Celcius mass of water in a cup: 75g the initial temperature of water: 24.7 degrees Celcius the final temperature of metal and water mix: 34.2 degrees celsius specific heat of water: 4.184 j/g degrees celsius specific heat of metal: 15.8 j/g celsius
How do I solve for the percentage of error of the experiment? Data table: mass of empty 8'' test tube: 41.47 mass of test tube and metal: 91.59 the initial temperature of metal: 10.5 degrees Celcius mass of water in a cup: 75g the initial temperature of water: 24.7 degrees Celcius the final temperature of metal and water mix: 34.2 degrees celsius specific heat of water: 4.184 j/g degrees celsius specific heat of metal: 15.8 j/g celsius
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I solve for the percentage of error of the experiment?
Data table:
mass of empty 8'' test tube: 41.47
mass of test tube and metal: 91.59
the initial temperature of metal: 10.5 degrees Celcius
mass of water in a cup: 75g
the initial temperature of water: 24.7 degrees Celcius
the final temperature of metal and water mix: 34.2 degrees celsius
specific heat of water: 4.184 j/g degrees celsius
specific heat of metal: 15.8 j/g celsius
Expert Solution
Step 1
Given,
mass of empty 8'' test tube= 41.47g
mass of test tube and metal= 91.59 g
Therefore mass of metal
Initial temperature of metal
Final temperature of metal and water mix
Mass of water
initial temperature of water
Specific heat of water
Specific heat of metal (given)
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