How do i prove 8.10? Could you include step by step explanation? Theorem 8.10 (Intermediate Value Theorem). Let ƒ : Rstdmap. If a, b e R and r is a point of R such that f(a) < r < f(b), then there exists a pointc in (a, b) such that f(c) = r.Rstd be a continuousDefinition. Let X be a topological space. Then X is connected if and only if X is notthe union of two disjoint non-empty open sets.Definition. Let X be a topological space. Subsets A, B in X are separated if and onlyif ANB = AnB = Ø. Thus B does not contain any limit points of A, and A does notcontain any limit points of B. The notation Xare separated sets.= A | B means X = A U B and A and BTheorem 8.1. The following are equivalent:(1) X is connected.(2) There is no continuous function f : X -Rstd such that f(X) = {0,1}.(3) X is not the union of two disjoint non-empty separated sets.(4) X is not the union of two disjoint non-empty closed sets.(5) The only subsets of X that are both closed and open in X are the empty set andX itself.(6) For every pair of points p and q and every open cover {Uq}aeA of X there exist a finitenumber of the Ua's, {Ug,, Ua,, Ua,,.. , Ug,} such that p E Ug,, q E Ug,, and for eachi < n, Ua, n Uau + Ø.di+1Theorem 8.3. The space Rstd is connected.Theorem 8.5. Let{Ca}«ca be a collection of connected subsets of X, and let E be anotherconnected subset of X such that for each a in 1, En Ca # Ø. Then E U (U.rea Ca) isαελсоппеcted.Theorem 8.6. Let C be a connected subset of the topological space X. If D is a subset ofX such that C CDC C, then D is connected.Theorem 8.9. Let f : X → Y be a continuous, surjective function. If X is connected,then Y is connected.

Consider the equation ∆ABC where E is the midpoint of ABF is the some point on AC& EF||BCF is the mid point of ACThrough c draw CM||ABExtend EF and let it cut CM at D.

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How do i prove 8.10? Could you include step by step explanation?

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ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

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How do i prove 8.10? Could you include step by step explanation?

Theorem 8.10 (Intermediate Value Theorem). Let ƒ : Rstd
map. If a, b e R and r is a point of R such that f(a) < r < f(b), then there exists a point
c in (a, b) such that f(c) = r.
Rstd be a continuous
Definition. Let X be a topological space. Then X is connected if and only if X is not
the union of two disjoint non-empty open sets.
Definition. Let X be a topological space. Subsets A, B in X are separated if and only
if ANB = AnB = Ø. Thus B does not contain any limit points of A, and A does not
contain any limit points of B. The notation X
are separated sets.
= A | B means X = A U B and A and B
Theorem 8.1. The following are equivalent:
(1) X is connected.
(2) There is no continuous function f : X -
Rstd such that f(X) = {0,1}.
(3) X is not the union of two disjoint non-empty separated sets.
(4) X is not the union of two disjoint non-empty closed sets.
(5) The only subsets of X that are both closed and open in X are the empty set andX itself.
(6) For every pair of points p and q and every open cover {Uq}aeA of X there exist a finite
number of the Ua's, {Ug,, Ua,, Ua,,.. , Ug,} such that p E Ug,, q E Ug,, and for each
i < n, Ua, n Uau + Ø.
di+1
Theorem 8.3. The space Rstd is connected.
Theorem 8.5. Let{Ca}«ca be a collection of connected subsets of X, and let E be another
connected subset of X such that for each a in 1, En Ca # Ø. Then E U (U.rea Ca) is
αελ
соппеcted.
Theorem 8.6. Let C be a connected subset of the topological space X. If D is a subset of
X such that C CDC C, then D is connected.
Theorem 8.9. Let f : X → Y be a continuous, surjective function. If X is connected,
then Y is connected.

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