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How do I find the last part for D

How do I find the last part for D

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I find the last part for D
[Review Topics] This question has multiple parts. Work all the parts to get the most points. Aluminum chloride, AlCl3, is made by treating scrap aluminum with chlorine. 2 Al(s) + 3 Cl₂(g) → 2 AlCl3 (8) If you begin with 2.70 g of Al and 4.96 g of Cl₂, F2 a which reactant is limiting? Cl₂ Drag and drop your selection from the following list to complete the answer: Al AIC13 2.70 g Al x 1. Calculate the amounts of each reactant. 2. Compare the ratio of reactants amounts to the stoichiometric ratio defined by the equation. 4.96 g Cl₂ x 1 mol Al 26.98 g 0.100 mol Al 0.0700 mol Cl₂ Cl₂ is the limiting reactant. 80 F3 1 mol Cl₂ 70.90 g = = 0.100 mol Al 1.43 mol Al > 1 mol Cl₂ b What mass of AlCl3 can be produced? Show Hint Q = 0.0700 mol Cl₂ F4 2 mol Al 3 mol Cl₂ Cengage Learning | Cengage Technical Support 0 F5 C Correct F6 « F7 [References] DII F8 F9 1 F10 < Email F11
Transcribed Image Text:[Review Topics] This question has multiple parts. Work all the parts to get the most points. Aluminum chloride, AlCl3, is made by treating scrap aluminum with chlorine. 2 Al(s) + 3 Cl₂(g) → 2 AlCl3 (8) If you begin with 2.70 g of Al and 4.96 g of Cl₂, F2 a which reactant is limiting? Cl₂ Drag and drop your selection from the following list to complete the answer: Al AIC13 2.70 g Al x 1. Calculate the amounts of each reactant. 2. Compare the ratio of reactants amounts to the stoichiometric ratio defined by the equation. 4.96 g Cl₂ x 1 mol Al 26.98 g 0.100 mol Al 0.0700 mol Cl₂ Cl₂ is the limiting reactant. 80 F3 1 mol Cl₂ 70.90 g = = 0.100 mol Al 1.43 mol Al > 1 mol Cl₂ b What mass of AlCl3 can be produced? Show Hint Q = 0.0700 mol Cl₂ F4 2 mol Al 3 mol Cl₂ Cengage Learning | Cengage Technical Support 0 F5 C Correct F6 « F7 [References] DII F8 F9 1 F10 < Email F11
bwhat mass of AlCl3 can be produced? Mass= 6.22 g 7.00 x 10-2 mol Cl₂ × Calculate the mass of product based on the amount of the limiting reactant. 2 mol AlCl3 3 mol Cla 7.00 x 10-2 mol Cl₂ x X 133.3 g 1 mol AlCl3 CWhat mass of the excess reactant remains when the reaction is completed? Mass=1.441 9 Submit [Review Topics] d Set up an amounts table for this problem. Equation 2 Al(s) Initial amount (mol) 1.00x10^-1 Change (mol) Show Hint 2.70 g Al available - 1.26 g Al used = 1.44 g Al remains Determine the mass of the second reactant required in the reaction from the limiting reactant in a similar c reagent is the difference between its starting mass and what was used in the reaction. Correct 2 mol Al 26.98 g X 3 mol Cl₂ = 1.26 g Al used 1 mol Al 6.22 g AIC13 + 3 Cl₂ (g) 7.00x10^-2 -7.00x10^-2 Correct → 2 AlCl3 (s) 0 [References] Cengage Learning | Cengage Technical Support
Transcribed Image Text:bwhat mass of AlCl3 can be produced? Mass= 6.22 g 7.00 x 10-2 mol Cl₂ × Calculate the mass of product based on the amount of the limiting reactant. 2 mol AlCl3 3 mol Cla 7.00 x 10-2 mol Cl₂ x X 133.3 g 1 mol AlCl3 CWhat mass of the excess reactant remains when the reaction is completed? Mass=1.441 9 Submit [Review Topics] d Set up an amounts table for this problem. Equation 2 Al(s) Initial amount (mol) 1.00x10^-1 Change (mol) Show Hint 2.70 g Al available - 1.26 g Al used = 1.44 g Al remains Determine the mass of the second reactant required in the reaction from the limiting reactant in a similar c reagent is the difference between its starting mass and what was used in the reaction. Correct 2 mol Al 26.98 g X 3 mol Cl₂ = 1.26 g Al used 1 mol Al 6.22 g AIC13 + 3 Cl₂ (g) 7.00x10^-2 -7.00x10^-2 Correct → 2 AlCl3 (s) 0 [References] Cengage Learning | Cengage Technical Support
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