77. an = (In 3 In 2) + (ln 4 − ln 3) + (ln 5 − ln 4) + - - + (In (n − 1) - ln (n − 2)) + (lnn − ln(n − 1)) - - -

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question

Find if the sequence converges or diverges and state the limit of a convergent sequence. The given sequence is below: 

**Problem 77:**

Evaluate the series given by \( a_n \):

\[ a_n = (\ln 3 - \ln 2) + (\ln 4 - \ln 3) + (\ln 5 - \ln 4) + \cdots + (\ln (n - 1) - \ln (n - 2)) + (\ln n - \ln (n - 1)) \]

Breaking down the expression for \(a_n\) into its components, you notice that each term of the form \( (\ln k - \ln (k-1)) \) for \( k = 3 \) to \( k = n \). This implies that each negative logarithm term cancels with the positive logarithm term of the subsequent term in the series. Consequently, this series is telescoping.

By cancellation, it simplifies to:

\[ a_n = \ln n - \ln 2 = \ln \left( \frac{n}{2} \right) \]

Hence, the final value for \( a_n \) is:

\[ a_n = \ln \left( \frac{n}{2} \right) \]
Transcribed Image Text:**Problem 77:** Evaluate the series given by \( a_n \): \[ a_n = (\ln 3 - \ln 2) + (\ln 4 - \ln 3) + (\ln 5 - \ln 4) + \cdots + (\ln (n - 1) - \ln (n - 2)) + (\ln n - \ln (n - 1)) \] Breaking down the expression for \(a_n\) into its components, you notice that each term of the form \( (\ln k - \ln (k-1)) \) for \( k = 3 \) to \( k = n \). This implies that each negative logarithm term cancels with the positive logarithm term of the subsequent term in the series. Consequently, this series is telescoping. By cancellation, it simplifies to: \[ a_n = \ln n - \ln 2 = \ln \left( \frac{n}{2} \right) \] Hence, the final value for \( a_n \) is: \[ a_n = \ln \left( \frac{n}{2} \right) \]
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Follow-up Questions
Read through expert solutions to related follow-up questions below.
Follow-up Question

how did you get ln n - ln 2

Solution
Bartleby Expert
SEE SOLUTION
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning