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How did you (1) get the x-table number (please show step by step without taking short-cuts. (2) how did you get - 0.5244 from 33-38/SD when I only got -5

How did you (1) get the x-table number (please show step by step without taking short-cuts. (2) how did you get - 0.5244 from 33-38/SD when I only got -5

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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How did you (1) get the x-table number (please show step by step without taking short-cuts. (2) how did you get - 0.5244 from 33-38/SD when I only got -5? What am I missing?
1:16 ← I used z-table to calculate the probability and quantile for standard normal distribution. Step2 b) Let x denote the repair time. Given that. a) Given that 40% of the units repaired b/w 33 and 43 min. ⇒ P (33 < X < 43) = 0.40 are Using standardization. P(33-M LX-MC → 33-38 Step3 XN Normal (M= 38 min.) Using 2-table, 33-38 - 43-M 5 <2<43-38). = 0.40, where I is the mean and is the sd. = 0.40 where 2 is that Standard normal variate. ZN Normal (0, 1) ? LTE 43-38 5 = 50.5244 6 = sd = 9.535 min. 2 = -0.5244 and =0.5244 -5/6=-0.5244 and $=0.5244 √x Do 8
Transcribed Image Text:1:16 ← I used z-table to calculate the probability and quantile for standard normal distribution. Step2 b) Let x denote the repair time. Given that. a) Given that 40% of the units repaired b/w 33 and 43 min. ⇒ P (33 < X < 43) = 0.40 are Using standardization. P(33-M LX-MC → 33-38 Step3 XN Normal (M= 38 min.) Using 2-table, 33-38 - 43-M 5 <2<43-38). = 0.40, where I is the mean and is the sd. = 0.40 where 2 is that Standard normal variate. ZN Normal (0, 1) ? LTE 43-38 5 = 50.5244 6 = sd = 9.535 min. 2 = -0.5244 and =0.5244 -5/6=-0.5244 and $=0.5244 √x Do 8
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