How did we get 40 in the last solution? How did we get (k+2) and (2k+1)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How did we get 40 in the last solution? How did we get (k+2) and (2k+1)?

Expert Solution
Step 1: Determine the given variables

Given that :- sum from k equals 1 to n of open parentheses 1 to the power of 4 plus 2 to the power of 4 plus 3 to the power of 4 plus........ plus n to the power of 4 close parentheses equals fraction numerator n left parenthesis n plus 1 right parenthesis left parenthesis 2 n plus 1 right parenthesis left parenthesis 3 n squared plus 3 n minus 1 right parenthesis over denominator 30 end fraction

To Prove :- Using Mathematical induction showing the left and right are equal.


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