26. da (x² cos y+ sin 2y) =(ry) x(- sin y y') + (cos y)(2z) + cos 2y - 2y = x-y' +y·1 = %3D %3D dx y-2x cos y 2 cos 2y- sin y-z y'(-a sin y+2 cos 2y-a) =y- 2x cos y y' 27 11- (1 -1)-1
26. da (x² cos y+ sin 2y) =(ry) x(- sin y y') + (cos y)(2z) + cos 2y - 2y = x-y' +y·1 = %3D %3D dx y-2x cos y 2 cos 2y- sin y-z y'(-a sin y+2 cos 2y-a) =y- 2x cos y y' 27 11- (1 -1)-1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
How do you get the y' and 2y' in number 26
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F.
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28.
2 sec 20 |(1+tan 20) tan 20- sec 20
(1+tan 20)2
(1+tan 20)²
2 sec 20 (tan 20 +tan 20- sec2 20)
(1+tan 20)²
2 sec 20 (tan 20 -1)
(1+tan 20)2
1+tanz= sec² z]
26.
(z cos y+ sin 2y) =(ry) z°(- sin y · y') + (cos y)(2z) + cos 2y - 2y' = z - y' + y · 1 →
(ry) x(-sin y · y')+ (cos y)(2x)+ cos 2y - 2y' = x - y' +y·1 =
%3D
y-2x cos y
'(a² sin y+2 cos 2y-) y- 2r cos y y'
|
%3D
2 cos 2y - sin y -a
27. y = (1--1)-1 =
y = -1(1-#-1)-2-(-lz-2)] = -(1-1/z)-2x-2 =-((x-1)/피)-z-2=-(z-1)-2
28. y =
%3D
29. sin(ry) = 2 -y = cos(ry)(xy' +y 1) = 2z- y z cos(xy)y' + y' = 2z – y cos(zy) >
%3D
y [x cos(ry)+ 1] = 2x-y cos(ry) = y =
2x-y cos(ry)
x cos(zy) +1
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F.
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28.
2 sec 20 |(1+tan 20) tan 20- sec 20
(1+tan 20)2
(1+tan 20)²
2 sec 20 (tan 20 +tan 20- sec2 20)
(1+tan 20)²
2 sec 20 (tan 20 -1)
(1+tan 20)2
1+tanz= sec² z]
26.
(z cos y+ sin 2y) =(ry) z°(- sin y · y') + (cos y)(2z) + cos 2y - 2y' = z - y' + y · 1 →
(ry) x(-sin y · y')+ (cos y)(2x)+ cos 2y - 2y' = x - y' +y·1 =
%3D
y-2x cos y
'(a² sin y+2 cos 2y-) y- 2r cos y y'
|
%3D
2 cos 2y - sin y -a
27. y = (1--1)-1 =
y = -1(1-#-1)-2-(-lz-2)] = -(1-1/z)-2x-2 =-((x-1)/피)-z-2=-(z-1)-2
28. y =
%3D
29. sin(ry) = 2 -y = cos(ry)(xy' +y 1) = 2z- y z cos(xy)y' + y' = 2z – y cos(zy) >
%3D
y [x cos(ry)+ 1] = 2x-y cos(ry) = y =
2x-y cos(ry)
x cos(zy) +1
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impr.écr.
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