How did he/she get the -j0.01963? I got different answer :(

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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How did he/she get the -j0.01963? I got different answer :(

Simplify the expression.
-0.49982 -0.0205467755
9(-16.006482-j5.658)
(-16.006482)²+(5.658)²
Transcribed Image Text:Simplify the expression. -0.49982 -0.0205467755 9(-16.006482-j5.658) (-16.006482)²+(5.658)²
Given-
9 = B (-1-j 2, 829) (-1-j2²829 + 1-j2.829)
9 = B (-1-jp. 829) (-j2.829-j2.829)
9 = B (+-ja. 29) (-15.658)
9 = B [√5.658 + (j)² 16.006 482
9 = B ( √5.658-16.00 6482) {√² =-1}
9
B =
(√5.658-16.006482)
on rationalizing,
9
B =
(J5.658-16.006482)
=
X
-16.00 6482-j5.658
BE -0.5 - jo⋅ 1768
-16.006482-5.658
9 (-16.006482-√5.658)
(-16.00 6482)² + (5.658) 2
= 9 (-0.05554-j0.01963)
= -0.4998 - jo-1768
Transcribed Image Text:Given- 9 = B (-1-j 2, 829) (-1-j2²829 + 1-j2.829) 9 = B (-1-jp. 829) (-j2.829-j2.829) 9 = B (+-ja. 29) (-15.658) 9 = B [√5.658 + (j)² 16.006 482 9 = B ( √5.658-16.00 6482) {√² =-1} 9 B = (√5.658-16.006482) on rationalizing, 9 B = (J5.658-16.006482) = X -16.00 6482-j5.658 BE -0.5 - jo⋅ 1768 -16.006482-5.658 9 (-16.006482-√5.658) (-16.00 6482)² + (5.658) 2 = 9 (-0.05554-j0.01963) = -0.4998 - jo-1768
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