How did he get the value (jw) ² x 10) = Uw)² x1w) = w2x/m) 1 inside the circle wa) A е (b-a) [ (@jwb _e-jwb) - (etwa etway) sin (bw) - sin(aw) ] 21 A (b-a) D sin (bw) - sin (aw)
How did he get the value (jw) ² x 10) = Uw)² x1w) = w2x/m) 1 inside the circle wa) A е (b-a) [ (@jwb _e-jwb) - (etwa etway) sin (bw) - sin(aw) ] 21 A (b-a) D sin (bw) - sin (aw)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![How did he get the
value inside the circle wa).
(jw)² x 160) =
(jw) ² x1w) =
-w2x/w) =
A
(b-a)
X16) =
x1w) =
е
е
-e-jwb) - (etwa - ejeg)
[ (@jwb _e-jwb).
sin (bw) - sin (aw)]
21A
(b-a)
25+ [sin (bu)- sin(aco)]
(b-a)
(-2)) A (sin (bu) - sin (Aw))
-
(21) A (sin (aw) - sin(bw))
(b-a)
W2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8cb083b9-25f4-45a4-bd34-91cb11bd19c4%2Fdbac3c3a-6feb-4619-b255-8b41907b4afd%2Fmt2mz9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:How did he get the
value inside the circle wa).
(jw)² x 160) =
(jw) ² x1w) =
-w2x/w) =
A
(b-a)
X16) =
x1w) =
е
е
-e-jwb) - (etwa - ejeg)
[ (@jwb _e-jwb).
sin (bw) - sin (aw)]
21A
(b-a)
25+ [sin (bu)- sin(aco)]
(b-a)
(-2)) A (sin (bu) - sin (Aw))
-
(21) A (sin (aw) - sin(bw))
(b-a)
W2
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