How did he get the value inside the circle? Can you explain step by step and clear line please? B = 156- 58 [78.35° I = 840 /-Cosb.85 = 840/-31-79° n = 275 x 163 = 158-77Lw [P hase] Calculate Vsi I,nletticiency),s(torque ang les PLOSS '. AD-BC = 1 (o•861L) (0.8611°) - 1 C = A.D -1 15C.581구8-3s° c= l•663 X 10/9 5 · 348 as we know that

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter14: Basic Trigonometry And Vectors
Section: Chapter Questions
Problem 5RQ: 5. The hypotenuse has a length of 65 in., and side A has a length of 31 in. What is angle X?
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How did he get the value inside the circle?
Can you explain step by step and
clear line please?
B = 156- 58 [78.35°
I- 840 /-cos b.85 = 840-31-75° A
840/-Coso.85
- 275 X10%° =
= 840/-31-79° A
%3D
'=158.77Le w [p hase]
Calculate īs , Is i
nletticiency), Sl torque ang les
PLOSS
'. AD-BC= 1
A.D - 1
(0•861L)(0.8611°)-1
C =
. SE. 8t / 85.9SI
C= l.663 x l/95 - 348°
as we knowhat
Vs = A VR + B IR
%3D
Is = cVR + D Ie
%3D
Transcribed Image Text:How did he get the value inside the circle? Can you explain step by step and clear line please? B = 156- 58 [78.35° I- 840 /-cos b.85 = 840-31-75° A 840/-Coso.85 - 275 X10%° = = 840/-31-79° A %3D '=158.77Le w [p hase] Calculate īs , Is i nletticiency), Sl torque ang les PLOSS '. AD-BC= 1 A.D - 1 (0•861L)(0.8611°)-1 C = . SE. 8t / 85.9SI C= l.663 x l/95 - 348° as we knowhat Vs = A VR + B IR %3D Is = cVR + D Ie %3D
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