How can you look for cycles in a graph using the union find data structure? Before using uf.connect() on two adjacent points, first check if they're connected. If they're connected, it means there's a cycle. O b. You cannot use union find to find cycles. O c. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is a cycle. O d. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is no cycle. e. Before using uf.connect() on two adjacent points, first check if they're connected. If they're not connected, it means there's a cycle.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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How can you look for cycles in a graph using the union find data structure?
Before using uf.connect() on two adjacent points, first check if they're connected. If
they're connected, it means there's a cycle.
O b. You cannot use union find to find cycles.
O c. You run uf.connect() on all possible connections. If at least one node is not
connected, then it means there is a cycle.
O d. You run uf.connect() on all possible connections. If at least one node is not
connected, then it means there is no cycle.
Before using uf.connect() on two adjacent points, first check if they're connected. If
they're not connected, it means there's a cycle.
Transcribed Image Text:How can you look for cycles in a graph using the union find data structure? Before using uf.connect() on two adjacent points, first check if they're connected. If they're connected, it means there's a cycle. O b. You cannot use union find to find cycles. O c. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is a cycle. O d. You run uf.connect() on all possible connections. If at least one node is not connected, then it means there is no cycle. Before using uf.connect() on two adjacent points, first check if they're connected. If they're not connected, it means there's a cycle.
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