How can one find the Fourier series of f(x)=x^3 -(pi^2)*x based on knowing the cosine Fourier series for f(x)=x? I first did it using the x series in sines and integrating it twice, and that comes out easily, but can't understand how to do it starting with the cosines version of f(x)=x, which is given as x =pi/2 + sum [(2[-1^n)-1] cos(nx)/(pi*n^2)]
How can one find the Fourier series of f(x)=x^3 -(pi^2)*x based on knowing the cosine Fourier series for f(x)=x? I first did it using the x series in sines and integrating it twice, and that comes out easily, but can't understand how to do it starting with the cosines version of f(x)=x, which is given as x =pi/2 + sum [(2[-1^n)-1] cos(nx)/(pi*n^2)]
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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How can one find the Fourier series of f(x)=x^3 -(pi^2)*x based on knowing the cosine Fourier series for f(x)=x? I first did it using the x series in sines and integrating it twice, and that comes out easily, but can't understand how to do it starting with the cosines version of f(x)=x, which is given as x =pi/2 + sum [(2[-1^n)-1] cos(nx)/(pi*n^2)]
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