How can it be proven that the diagonals bisect each other? Drag tiles to the empty boxes to correctly complete each part of the proof. AB¯ ∥DC¯¯ because it is -- AB¯¯¯¯≅ DC¯¯ because opposite sides of parallelograms are congruent. ∠BAC≅∠DCA because they are --- angles. ∠AEB ≅∠CED because they are --- angles. △AEB ≅△CED because ---. BE¯ ≅ DE
Consider parallelogram ABCD.
How can it be proven that the diagonals bisect each other? Drag tiles to the empty boxes to correctly complete each part of the proof.
AB¯ ∥DC¯¯ because it is --
AB¯¯¯¯≅ DC¯¯ because opposite sides of parallelograms are congruent.
∠BAC≅∠DCA because they are ---
∠AEB ≅∠CED because they are --- angles.
△AEB ≅△CED because ---.
BE¯ ≅ DE¯ and AE¯ ≅ CE¯ because corresponding parts of congruent
So, AC¯ bisects BD¯ and BD¯ bisectsAC¯ because of the definition of a segment bisector.
Answer choices ( go in the --- ) : AAS ; ASA ; SAS ; SSS ; given ; corresponding ; verticle ; alternate interior ; alternate exterior ; same-side interior.
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