Houghton Mifflin Harcourt Publishing Company 3 PROOF Inscribed Quadrilateral Theorem Given: Quadrilateral ABCD is inscribed in circle O. Prove: LA and LC are supplementary; LB and D are supplementary. ABCD and DAB make a complete circle. Therefore, B mBCD + mDAB = 360° ZA is an inscribed angle and its intercepted arc is BCD; LC is an inscribed angle and its intercepted arc is DAB. By the Inscribed Angle Theorem, mZA= and m/C= C So, mZA+mZC=. Substitution Distributive Property Substitution Simplify. This shows that LA and ZC are supplementary. Similar reasoning shows that LB and 2D are supplementary. B

Elementary Geometry For College Students, 7e
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B and C please they are short answers

Houghton Mifflin Harcourt Publishing Company
3 PROOF
Inscribed Quadrilateral Theorem
Given: Quadrilateral ABCD is inscribed in circle O.
Prove: LA and LC are supplementary;
LB and D are supplementary.
ABCD and DAB make a complete circle. Therefore,
B
mBCD + mDAB = 360°
ZA is an inscribed angle and its intercepted arc is BCD; LC is an inscribed angle
and its intercepted arc is DAB. By the Inscribed Angle Theorem,
mZA=
and m/C=
C So, mZA+mZC=.
Substitution
Distributive Property
Substitution
Simplify.
This shows that LA and ZC are supplementary. Similar reasoning shows that
LB and 2D are supplementary.
B
Transcribed Image Text:Houghton Mifflin Harcourt Publishing Company 3 PROOF Inscribed Quadrilateral Theorem Given: Quadrilateral ABCD is inscribed in circle O. Prove: LA and LC are supplementary; LB and D are supplementary. ABCD and DAB make a complete circle. Therefore, B mBCD + mDAB = 360° ZA is an inscribed angle and its intercepted arc is BCD; LC is an inscribed angle and its intercepted arc is DAB. By the Inscribed Angle Theorem, mZA= and m/C= C So, mZA+mZC=. Substitution Distributive Property Substitution Simplify. This shows that LA and ZC are supplementary. Similar reasoning shows that LB and 2D are supplementary. B
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