Hospital Emergency room accepts an average of about 28 bone fracture patients a week that requiredajesources available with this demand accordingly. What is the probability that on any given day no more than one fracture patients arrive at the emergency room?
Hospital Emergency room accepts an average of about 28 bone fracture patients a week that requiredajesources available with this demand accordingly. What is the probability that on any given day no more than one fracture patients arrive at the emergency room?
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![Problem 4
Hospital Emergency room accepts an average of about 28 bone fracture patients a
week that requiredbajesources available with this demand accordingly.
What is the probability that on any given day no more than one fracture patients
arrive at the emergency room?
Use Poisson dist. Function with [2=28/7-4 patients/day; x-0 and x=1]
e-^ λx
9.2
% P(x)
=
x!
P(x≤1)=P(x=0)+P(x-1)= 0.092= 9.2 %](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6aad8a00-c703-485c-bf76-99694ae31b4b%2Fa0cbeae6-0d2e-4e6f-9757-33ec07f26271%2Fula1sq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem 4
Hospital Emergency room accepts an average of about 28 bone fracture patients a
week that requiredbajesources available with this demand accordingly.
What is the probability that on any given day no more than one fracture patients
arrive at the emergency room?
Use Poisson dist. Function with [2=28/7-4 patients/day; x-0 and x=1]
e-^ λx
9.2
% P(x)
=
x!
P(x≤1)=P(x=0)+P(x-1)= 0.092= 9.2 %
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