horizontal circle at constant speed vas shown below. The mass of the stopper is m and the hanging mass is M. The length of the string between the stopper and the tube is L.
horizontal circle at constant speed vas shown below. The mass of the stopper is m and the hanging mass is M. The length of the string between the stopper and the tube is L.
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e. How does this expression for the speed simplify if is very small, i.e., zero? Answer in terms of and .
Please I only need help with part e and the table with the problems under it
Transcribed Image Text:horizontal circle at constant speed vas shown below. The mass of the stopper is m and the hanging mass is M. The
length of the string between the stopper and the tube is L.
side view
FBD for stopper m
m
stopper
8
L
hanging mass
M
glass tube
+y
>+x
FBD for M
(stopper) x:
Write Newton's 2nd law in the y direction for the hanging mass
O
(hanging mass) y:
d. Determine the speed in terms of m, M, L, g and 8:
M
PREDICTION: Use your knowledge of dynamics and circular motion kinematics to predict the speed.
a. Draw the free body diagram for the stopper and for the hanging mass. To the right of the "=" draw an arrow
labeled "ma" or "Ma" in the direction of the acceleration or write zero if the acceleration is zero.
b. Write Newton's 2nd law in the x direction for the stopper. Recall what you know about the acceleration for
uniform circular motion and be careful with "r" - it is not equal to "L".
=
Transcribed Image Text:For the experiment, we pass the string through a glass tube. The hanging mass is tied to one end of the string and then
the stopper is tied to the other with the glass tube in between (see diagram on previous page).
While holding the glass tube, we twirl the stopper around in a horizontal circle above your head fast enough so the angle
Ⓒ is very small. We adjust the speed of the stopper and length of the string so that the hanging mass is suspended at a
common height. We use a stopwatch to measure the time for 5 complete periods and then measure the length of the
string between the stopper and glass tube. This is repeated for three trials.
Use the average period and radius to find the experimental speed for each trial.
2πL
Vexper = T
Use your result from part e in your analysis on the previous page for the predicted speed.
Include units wherever appropriate.
Time for 5
revolutions
2.8 sec
Trial
1
2
3
3.4 sec
2.5 sec
Average
period (T)
"pred =
Length
0.95 m
1.10 m
0.70 m
MgL
m
Speed
Speed
(experiment) (predicted)
% discrepancy
Show a sample calculation for the experimental speed, predicted speed, and the % discrepancy.3
What are valid reasons why the predicted value and the experimental value might not agree, i.e., what assumptions
used in our prediction might not be true?
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