Is honey a cough remedy? Refer to the Archives ofPediatrics and Adolescent Medicine (Dec. 2007) studyof honey as a children's cough remedy, Exercise 2.31(p. 62). Children who were ill with an upper respiratorytract infection and their parents participated in the study.Parents were instructed to give their sick child a dosageof liquid "medicine" prior to bedtime. Unknown to theparents, some were given a dosage of dextromethorphan(DM)–an over-the-counter cough medicine– whileothers were given a similar dose of honey. (Note: A thirdgroup gave their children no medicine.) Parents thenrated their children's cough symptoms, and the improve-ment in total cough symptoms score was determined foreach child. The data (improvement scores) for the 35children in the DM dosage group and the 35 childrenin the honey dosage group are reproduced in the nexttable. Do you agree with the statement (extracted fromthe article), “Honey may be a preferable treatment for thecough and sleep difficulty associated with childhood upperrespiratory tract infection"? Use the comparison of twomeans methodology presented in this section to answerthe question. Honey Dosage:12 11 15 11 10 13 10 4 15 16 9 14 10 6 10 8 1112 12 8 12 9 11 15 10 159 13 8 12 10 8 9 5 12DM Dosage:4 7 77 9 12 10 11 6 3 4 9 7 84 6 912 12 4 12 13 7 10 13 9 4 4 10 15 9 12 6Source: I. M. Paul et al., “Effect of Honey, Dextromethorphan, and NoTreatment on Nocturnal Cough and Sleep Quality for Coughing Children andTheir Parents," Archives of Pediatrics and Adolescent Medicine, Vol. 161,No. 12, December 2007 (data simulated).

A statistical hypothesis is an assumption or a statement about the population parameter. Hypothesis…

Answered: Honey Dosage: 12 11 15 11 10 13 10 4 15…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A mixture of sucrose and water was heated on a hot plate, and the temperature (in °C) was recorded each minute for 20 minutes by three thermocouples. The results are shown in the following table. Time 0 1 2 3 4 5 6 7 8 SPIEBALGAKOO | | 9 10 11 12 13 14 15 16 17 18 19 20 FO T1 20 18 29 32 37 36 46 46 56 58 64 72 79 84 82 87 98 103 107 103 102 H T2 18 22 22 25 37 46 45 44 54 64 69 65 80 74 87 93 90 100 100 103 103 T3 21 11 26 35 33 35 44 43 63 68 62 65 80 75 78 88 91 103 112 107 104 Someone else suggests averaging the three temperature measurements at each time to obtain T = (71+ 72 + 73)/3. Compute the 12 ‒‒‒ Next >
An experiment was implemented to test the effectiveness of a new veterinarian product for dogs. Animals were randomly assigned to two treatments. Dogs on group treatment A received the new product and control dogs on group treatment B received a placebo. At the end of the experiment the concentrations of a certain hormone (ng/ml) was measured and the following data was obtained: DATA: Observation 1 2 3 4 5 6 Trt A 13.7 11.7 13.4 12.7 12.4 10.8 Evaluate Ho: MA UB ---against--- HA: MA # MB Trt B 13.8 14.6 12.3 13.8 10.7 1. What is the calculated "t" statistics? (round to the nearest hundredth; place the absolute value of "t" in the box below) 2. Given your "t" calculated indicate if you are going to reject or fail to reject the null hypothesis using an alpha=0.1 (reject/fail to reject; place your answer right beside the calculated "t" statistics. Do not leave a space between the two answers)
step by step please
T-Mobile Wi-Fi ? 1 9:55 AM • 36% Done 14 of 18 FOL FIL FLL M F O Update i studeri.desmas.comiactivitybuilider/student/8088bcoe08264d0cod3ee897#screentc-beabee6: a5ct-4575-a535-f32a107ab362 E Sian in P View Portrait Pro. O Nursing: Tracition. 6 Legin Sessien Exolration. b Seling Assotiwe. Car tetiny tho.. O Emeloymert Cemter Aups a ntourse Carncc. く 10 of 14 Next > Unit 4. Lesson 14: Using Normal Distributions for Exper. Destry Orceu Rescarchers are tagging sharks using two different types of devices and want to know if the devices affect the heart rate of tho sharks. They tag one aroup of 8 sharks with a small device that collects a small amount of data and thoy tag another group of 8 sharks with a larger device that collects a large amount of data. They then measure the mean heart rate of the different groups and find that the difference in means is 2.5 beats per minute. Rescarchers run 1,000 simulations regrouping the data into 2 groups at random and record the differences in means…
Please fill out the last box using the data provided (Hypothesis test)
The table presents the highway gasoline mileage performance and engine displacement for DaimlerChrysler vehicles for model year 2005 (U.S. Environmental protection Agency). Engine Displacement (in³) 215 MPG (highway) 201 196 226 226 348 226 348 148 226 122 215 215 148 500 348 165 148 148 500 148 30.8 32.5 35.4 28.1 24.4 24.1 28.5 24.2 32.8 28.0 41.3 30.0 28.2 34.1 18.7 20.3 35.1 37.9 33.8 25.9 26.4 (a) Find a 95% confidence interval for the slope. Round your answers to three decimal places (e.g. 98.765). -0.056 < B₁ ≤ -0.024 (b) Find a 95% confidence interval for the intercept. Round your answers to two decimal places (e.g. 98.76). 34.96 < ßo ≤ 43.35 (c) Find a 95% confidence interval for the mean highway gasoline mileage when the engine displacement is x = 134 in³. Round I your answers to one decimal place (e.g. 98.7). ! MY|x=134 i (d) Construct a 95% prediction interval on highway gasoline mileage when the engine displacement is x = 134 in³. Round your answers to one decimal place…
this is supposed to be done using anovo
Data on weekday exercise time for 20 females, consistent with summary quantities given in the paper "An Ecological Momentary Assessment of the Physical Activity and Sedentary Behavior Patterns of University Students,"† are shown below. Female—Weekday 10.0 90.6 48.5 50.4 57.4 99.6 0.0 5.0 0.0 0.0 5.0 2.0 10.5 5.0 47.0 0.0 5.0 54.0 0.0 48.6 Calculate the values of the median and interquartile range. median: interquartile range: Interpret the values of the median and interquartile range. The median exercise time of indicates that half of the exercise times were below , and the remaining half were above . The interquartile range tells us that the middle fifty percent of exercise times had a range of .
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range: 415 421 422 423 426 429 431 434 436 439 445 446 448 453 455 463 464 (a) Construct a boxplot of the data. O 420 420 430 430 440 440 450 The data appears to be centered near 438. The data is strongly skewed. There is one outlier. 450 Comment on any interesting features. (Select all that apply.) There are no outliers. The data appears to be centered near 428. There is little or no skew. 460 420 420 430 430 (b) Is it plausible that the given sample observations were selected from a normal distribution? Yes No 440 440 450 450 460 460 (c) Calculate a two-sided 95% confidence interval for true average degree of polymerization. (Round your answers to two decimal places.)
The table below shows the lower back pain intensity scores for eight patients before and after receiving acupuncture for eight weeks. At a = 0.025, complete parts (a) through (e) to determine if there is enough evidence to conclude that the lower back pain intensity scores decreased after the acupuncture. Patient 1 2 3 4 5 7 8 Intensity score (before) Intensity score (after) 60.5 69.1 56.2 67.7 62.7 77.5 57.8 78.7 49.7 63.5 22.7 25.9 65.1 19.4 65.2 48.4 .... (a) Write the claim and identify Ho and Ha Which is the correct claim? O A. The lower back pain intensity scores have not decreased. O B. The lower back pain intensity scores increased. OC. The lower back pain intensity scores have not increased. O D. The lower back pain intensity scores decreased. Identify Ho and H, below. Họ is the lower back pain intensity scores Ha is the lower back pain intensity scores (b) Determine the critical value. The critical value is. (Type an integer or decimal rounded to the nearest hundredth as…
Test the claim Ho: Ps = 0 versus Ha: Ps # 0 that there is a significant correlation between purchased seed expenses and fertilizer and lime expenses in the farming business. The critical value is 0.738 %3D Seed Expenses Rank Fertilizer/lime Rank d. Expenses 480 490 1530 2060 490 480 266 402 741 642 380 470 879 858 360 560
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