Homework Question 3.45) Assume that the block has mass m = 0.2 kg and that the spring constant is k=57² kg/s². Suppose now that the block is pulled a distance of 2 cm from the equilibrium position of the spring and released from rest there at time t = 0. A) Find the position x(t) of the block at any time t. B) Give the amplitude, period, frequency and phase of the motion.

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Can you please answer question 3.45
Integrative Activity
Simple Harmonic Motion
This small self-learning project
is a mandatory part of the course.
Suppose we want to find a function y = f(t) such that its derivatives would satisfy the equation
y"+o²y=0
(DE)
where a (a Greek lowercase letter called omega) is a positive constant. Such an equation involving
a function y = f(t) and its derivatives together is called a differential equation. Solving a
differential equation does not consist in finding a number that fits an equation, the goal is rather to
find a function that fits an equation. In the above, the goal is to find which function y = f(t)
satisfies equation (DE).
In general, finding functions that solve a differential equation is quite hard. We sometimes offer
a course on differential equations in your last term! For the specific differential equation
y"+²y=0 that we have at hand, a solution is not too difficult. As you will verify below in
question 3.41B, any function of the form
y(t)= acos(at)+b sin(at)
(GS1)
where a and b are arbitrary constants, does satisfy differential equation (DE). Note that
y(t) = acos(at)+bsin(at) represents infinitely many possible functions due to the infinitely
many values that the arbitrary constants a and b can take. Moreover, it is shown in more advanced
mathematics courses that there are no other possible functions satisfying equation (DE), that is,
the infinitely many functions of equation (S1) give precisely all the possible functions that are
solutions of the differential equation (DE). We call (GS1) a general solution of (DE).
With some trigonometry, it can be shown that another way to write the general solution of (DE) is
(GS2)
y(t) = Acos(at + p)
where A and are constants and A is taken positive. As you will see in question 3.42 below, one
may switch between the two equivalent forms (GS1) and (GS2) of the general solution.
There are many physical situations that lead to a differential equation such as (DE), called the
(differential) equation of Simple Harmonic Motion; we will see one such example below. A
system whose position as a function of time must satisfy the equation of Simple Harmonic Motion
(DE), that is, whose position as a function of time will be given by a particular instance of equations
(GS1) or (GS2), is said to undergo Simple Harmonic Motion. Note that in (GS2) corresponds to
a "phase shift" (reason for the choice of the greak letter phi) compared to where the usual cosine
function starts:
dose
Pift
Amplitude
RTY
To aut
Transcribed Image Text:Integrative Activity Simple Harmonic Motion This small self-learning project is a mandatory part of the course. Suppose we want to find a function y = f(t) such that its derivatives would satisfy the equation y"+o²y=0 (DE) where a (a Greek lowercase letter called omega) is a positive constant. Such an equation involving a function y = f(t) and its derivatives together is called a differential equation. Solving a differential equation does not consist in finding a number that fits an equation, the goal is rather to find a function that fits an equation. In the above, the goal is to find which function y = f(t) satisfies equation (DE). In general, finding functions that solve a differential equation is quite hard. We sometimes offer a course on differential equations in your last term! For the specific differential equation y"+²y=0 that we have at hand, a solution is not too difficult. As you will verify below in question 3.41B, any function of the form y(t)= acos(at)+b sin(at) (GS1) where a and b are arbitrary constants, does satisfy differential equation (DE). Note that y(t) = acos(at)+bsin(at) represents infinitely many possible functions due to the infinitely many values that the arbitrary constants a and b can take. Moreover, it is shown in more advanced mathematics courses that there are no other possible functions satisfying equation (DE), that is, the infinitely many functions of equation (S1) give precisely all the possible functions that are solutions of the differential equation (DE). We call (GS1) a general solution of (DE). With some trigonometry, it can be shown that another way to write the general solution of (DE) is (GS2) y(t) = Acos(at + p) where A and are constants and A is taken positive. As you will see in question 3.42 below, one may switch between the two equivalent forms (GS1) and (GS2) of the general solution. There are many physical situations that lead to a differential equation such as (DE), called the (differential) equation of Simple Harmonic Motion; we will see one such example below. A system whose position as a function of time must satisfy the equation of Simple Harmonic Motion (DE), that is, whose position as a function of time will be given by a particular instance of equations (GS1) or (GS2), is said to undergo Simple Harmonic Motion. Note that in (GS2) corresponds to a "phase shift" (reason for the choice of the greak letter phi) compared to where the usual cosine function starts: dose Pift Amplitude RTY To aut
Suppose now that a block of mass m is attached to one end of a horizontal spring, the other end of
which is fixed. Using Newton's F=ma and the fact that a is x", Hooke's Law becomes a
differential equation: mx"=-kox or x"=-x. The acceleration of the mass is proportional to the
displacement from equilibrium. Putting =√k/m, we see that the system actually obeys the
differential equation of Simple Harmonic Motion:
x"+ @²x = 0.
Thus Simple Harmonic Motion is obtained as the motion undergone by a particle under a
restoring force proportional to the displacement (from an equilibrium point).
The solution for the motion of the system is consequently already known as being of the form
(GS1) or (GS2), taking
@=
Homework Question 3.45)
Assume that the block has mass m = 0.2 kg and that the spring constant is k=57² kg/s². Suppose
now that the block is pulled a distance of 2 cm from the equilibrium position of the spring and
released from rest there at time t = 0.
A) Find the position x(t) of the block at any time t.
B) Give the amplitude, period, frequency and phase of the motion.
Remarks: 1) The units for frequency are Hz or s¹, and the phase is an angle in radians (thus unitless).
2) For part A), you can use form (GS1) or (GS2) of the solution. Often working with (GS1) is simplest, but
when you are requested the phase, you may want to work directly with (GS2). Staring with (GS1) will
require you to use conversions found in 3.42 to obtain the phase.
sai 0 <sprw
homociqzib sizi x
bollas ai (1) noitsup
oli mul muindiliups utorit
363
Transcribed Image Text:Suppose now that a block of mass m is attached to one end of a horizontal spring, the other end of which is fixed. Using Newton's F=ma and the fact that a is x", Hooke's Law becomes a differential equation: mx"=-kox or x"=-x. The acceleration of the mass is proportional to the displacement from equilibrium. Putting =√k/m, we see that the system actually obeys the differential equation of Simple Harmonic Motion: x"+ @²x = 0. Thus Simple Harmonic Motion is obtained as the motion undergone by a particle under a restoring force proportional to the displacement (from an equilibrium point). The solution for the motion of the system is consequently already known as being of the form (GS1) or (GS2), taking @= Homework Question 3.45) Assume that the block has mass m = 0.2 kg and that the spring constant is k=57² kg/s². Suppose now that the block is pulled a distance of 2 cm from the equilibrium position of the spring and released from rest there at time t = 0. A) Find the position x(t) of the block at any time t. B) Give the amplitude, period, frequency and phase of the motion. Remarks: 1) The units for frequency are Hz or s¹, and the phase is an angle in radians (thus unitless). 2) For part A), you can use form (GS1) or (GS2) of the solution. Often working with (GS1) is simplest, but when you are requested the phase, you may want to work directly with (GS2). Staring with (GS1) will require you to use conversions found in 3.42 to obtain the phase. sai 0 <sprw homociqzib sizi x bollas ai (1) noitsup oli mul muindiliups utorit 363
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