- Homework - 2022.pdf - Adobe Acrobat Pro DC (32-bit) Sign Window Help Chapter 14 - Soluti. x 日 Q 玩。早2 。 / 3 135% 3) Determine the solubility (M) of N2 in water at 25°C if the pressure of N2 is 0.80 atm. The 3) _ Henry's law constant for nitrogen in water at this temperature is 6.4 x 10-4 M/atm.

- Homework - 2022.pdf - Adobe Acrobat Pro DC (32-bit) Sign Window Help Chapter 14 - Soluti. x 日 Q 玩。早2 。 / 3 135% 3) Determine the solubility (M) of N2 in water at 25°C if the pressure of N2 is 0.80 atm. The 3) _ Henry's law constant for nitrogen in water at this temperature is 6.4 x 10-4 M/atm.

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter10: Solutions

Section: Chapter Questions

Problem 78QAP: A gaseous solute dissolves in water. The solution process has H=15 kJ. Its solubility at 22C and...

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The Henry's law constant for the solubility of helium gas in water is 3.8104M/atm at 25C. (a) Express the constant for the solubility of helium gas in M/mm Hg. (b) If the partial pressure of He at 25C is 293 mm Hg, what is the concentration of dissolved He in mol/L at 25C? (c) What volume of helium gas can be dissolved in 10.00 L of water at 293 mm Hg and 25C? (Ignore the partial pressure of water.)
The Henry's law constant for the solubility of argon gas in water is 1.0103M/atm at 30C. (a) Express the constant in M/mm Hg. (b) If the partial pressure of argon gas at 30C is 693 mm Hg, what is the concentration (in M) of the dissolved argon gas at 30C? (c) How many grams of argon gas can be dissolved in 29 L of water at 693 mm Hg and 30C? (Ignore the partial pressure of water.)
A gaseous solute dissolves in water. The solution process has H=15 kJ. Its solubility at 22C and 6.00 atm is 0.0300 M. Would you expect the solubility to be greater or less at (a) 22C and 1 atm? (a) 18C and 6 atm? (a) 15C and 10 atm? (a) 35C and 3 atm?
Sodium chloride (NaCl) is commonly used to melt ice on roads during the winter. Calcium chloride (CaCl2) is sometimes used for this purpose too. Let us compare the effectiveness of equal masses of these two compounds in lowering the freezing point of water, by calculating the freezing point depression of solutions containing 200. g of each salt in 1.00 kg of water. (An advantage of CaCl2 is that it acts more quickly because it is hygroscopic, that is. it absorbs moisture from the air to give a solution and begin the process. A disadvantage is that this compound is more costly.)
Vapor-pressure lowering is a colligative property, as are freezing-point depression and boiling-point elevation. What is a colligative property? Why is the freezing point depressed for a solution as compared to the pure solvent? Why is the boiling point elevated for a solution as compared to the pure solvent? Explain how to calculate T for a freezing-point depression problem or a boiling-point elevation problem. Of the solvents listed in Table 10-5, which would have the largest freezing-point depression for a 0.50 molal solution? Which would have the smallest boiling-point elevation for a 0.50 molal solution? A common application of freezing-point depression and boiling-point elevation experiments is to provide a means to calculate the molar mass of a nonvolatile solute. What data are needed to calculate the molar mass of a nonvolatile solute? Explain how you would manipulate these data to calculate the molar mass of the nonvolatile solute.
You make 20.0 g of a sucrose (C12H22O11) and NaCl mixture and dissolve it in 1.00 kg water. The freezing point of this solution is found to be 0.426C. Assuming ideal behavior, calculate the mass percent composition of the original mixture, and the mole fraction of sucrose in the original mixture.
How do colloids differ from solutions with regard to dispersed particle size and homogeneity?
Using KF as an example, write equations that refer to Hsoln and Hhyd Lattice energy was defined in Chapter 3 as H for the reaction K+(g) + F (g) KF(s). Show how you would utilize Hesss law to calculate Hso1n from Hhyd and HLE for KF, where HLE = lattice energy. Hsoln for KF, as for other soluble ionic compounds, is a relatively small number. How can this be since Hhyd and HLE are relatively large negative numbers?
A 1.00 mol/kg aqueous sulfuric acid solution, H2SO4,freezes at 4.04 C. Calculate i, the vant Hoff factor,for sulfuric acid in this solution.
The solubility of ethylene (C2H4) in water at 20 C and 0.300 atm pressure is 1.27 104 molal. (a) Calculate the Henrys law constant for this gas in units of molal/torr. (b) How many grams of ethylene are dissolved in 1.00 kg water at 20 C if the pressure of the gas is 500 torr?
An aqueous solution containing 10.0 g of starch per liter has an osmotic pressure of 3.8 mm Hg at 25 C. (a) What is the average molar mass of starch? (The result is an average because not all starch molecules are identical.) (b) What is the freezing point of the solution? Would it be easy to determine the molecular weight of starch by measuring the freezing point depression? (Assume that the molarity and molality are the same for this solution.)
An unknown compound contains only carbon, hydrogen, and oxygen. Combustion analysis of the compound gives mass percents of 31.57% C and 5.30% H. The molar mass is determined by measuring the freezing-point depression of an aqueous solution. A freezing point of 5.20C is recorded for a solution made by dissolving 10.56 g of the compound in 25.0 g water. Determine the empirical formula, molar mass, and molecular formula of the compound. Assume that the compound is a nonelectrolyte.