Home » StudentsB Overview - MAT-133-X3581 Int X8-3 Homework: Chapter 8 (Sect X+https://newconnect.mheducation.com/flow/connect.html110%k: Chapter 8 (Sections 8.4 throug..iSavedHelpSave & ExitSuCheck my wCUse the sample information = 36, o = 4, n= 13 to calculate the following confidence intervals for u assuming the sample is from anormal population.(a) 90 percent confidence. (Round your answers to 4 decimal plates.)toThe 90% confidence interval is from(b) 95 percent confidence. (Round your answers to 4 decimal places.)toThe 95% confidence interval is from(c) 99 percent confidence. (Round your answers to 4 decimal places.)toThe 99% confidence interval is from(d) Describe how the intervals change as you increase the confidence level.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Student Documents... H Take Test: Test 1-. Stock Analysis.pdf -.. ** pasu OLume v Question Completion Status: QUESTION 7 A physician wants to determine the mean serum HDL cholesterol of all 20- to- 29 year old females. How many subjects are needed to estimate the mean serum HDL cholesterol of all 20-to-29 year old females within 2 points with 99% confidence assuming that s = 13.4 based on earlier studies? Show your work for full credit. Suppose that the physician would be content with 95% confidence. How does the decrease in confidence affect the sample size required? T T TT Paragraph Arial 3 (12pt) T T, HTML CSS fx • Mashups Words:0 Path: p QUESTION 8 Save Al An Click Save gnd Submit to save and submit. Click Save All Answers to save all answers.
21WB_MATH_1016_WBON Ashley Ramos & Homework: Unit 7 Homework Save Score: 0.83 of 5 pts 6 of 14 (11 complete) HW Score: 49.17%, 24.58 of 50 pts 7.2.31-T Question Help A random sample of 75 eighth grade students' scores on a national mathematics assessment test has a mean score of 293. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 285. Assume that the population standard deviation is 32. At a = 0.14, is there enough evidence to support the administrator's claim? Complete parts (a) through (e). (a) Write the claim mathematically and identify Ho and Ha. Choose the correct answer below. O A. Ho: H2285 (claim) O B. Ho: H= 285 (claim) Ha:H> 285 Ψc. H : μ# 285 Ha:H 285 (claim) OD. Ho:H= 285 Ο Ε. H : μ 285 Hai H> 285 (claim) (b) Find the standardized test statistic z, and its corresponding area. z = 2.17 (Round to two decimal places as needed.) (c) Find the P-value. P-value = (Round to three decimal…
a survey found 91% of 5101 us adults are concerned about how their children perform if school. using 96% confidence level find margin of error and assume normal distribution
A survey of 200 middle managers showed a distribution of the number of hours of exercise they participated in per week with a mean of 3.64 hours and a standard deviation of 4.76 hours. Complete parts (a) through (c) below. Question content area bottom Part 1 a) According to the Normal model, what percent of managers will exercise fewer than one standard deviation below the mean number of hours? (Round to the nearest whole number as needed.) Part 2 b) For these data, what does that mean? Explain. Select the correct choice below and fill in the answer box(es) within your choice. (Type integers or decimals.) A. One standard deviation below the mean is enter your response here hours. This means that enter your response here% of managers are exercising no more than this number of hours. B. One standard deviation below the mean is enter your response here hours. This means that enter your response here% of managers are exercising exactly this…
What can you determine from the two images and comparing the N, mean, st deviation, std error mean, F, sir, t, do, sig (2-tailed), mean difference, std error differences, and 95% confidence interval of the difference lower and upper. Please describe what you see from the data being presented
Q2) Independent-Samples t-Test (Round calculated results to the hundredth (2nd place to the right of the decimal)) In a research project, researchers collected demographic and health data from a sample of elderly residents in the community. To examine any possible gender differences in their sample, they want to see if the females and the males differ significantly on the education level (number of years of formal schooling). The researchers are not predicting any direction in the possible gender differences so the hypotheses should be non-directional. They would like to run a two-tailed test with α = .10. Male Subject ID Education Female Subject ID Education 1 14 13 14 2 15 14 15 3 17 15 18 4 13 16 18 5 15 17 16 6 15 18 17 7 13 19 16 8 15 20 16 9 15 21 17 10 16 22 15 11 17…
true or false ?
could you please tell me how to explain to a friend who does not know anything about statistics the relationship between the confidence level expressed as a confidence interval and the level of significance in hypothesis testing. Illustrate the relationship using either the critical value or the p-value approach.thanks
I need help with stats/2023, section 6.2 (please help with TI-84 commands please) Thanks Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a recent season, the population standard deviation of the yards per carry for all running backs was 1.27. The yards per carry of 25 randomly selected running backs are shown below. Assume the yards per carry are normally distributed. 2.4 5.4 5.9 4.6 3.5 4.9 4.9 6.8 3.2 1.3 2.6 4.1 5.2 7.3 3.5 4.1 2.8 4.9 3.8 6.4 5.6 4.4 ..........................6.9 6.5 3.8 Which distribution should be used to construct the confidence interval? A. Use a normal distribution because n<30, the data are normally distributed and σ is unknown. B. Use a t-distribution because n<30 and σ is unknown. C. Use a…
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If n = 420 and ˆpp^ (p-hat) = 0.05, construct a 95% confidence interval. Round three places.

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