hollow aluminum cylinder 19.5 cm deep has an internal capacity of 2.000L at 18.0°C. It is completely filled with turpentine at 18.0°C. aluminum is 2.4 x 10Sec-1, and the average volume expansion coefficient for turpentine is 9.0 x 10tc-1.) turpentine and the aluminum cylinder are then slowly warmed together to 70.0C. (The average linear expansio (a) How much turpentine overflows? em (b) What is the volume of turpentine remaining in the cylinder at 70.0°C? (Give you answer to four significant figures.) cm (c) If the combination with this amount of turpentine is then cooled back to 18.0°C, how far below the cylinder's rim does the turpentine's surface recede? cm Additional Materials
hollow aluminum cylinder 19.5 cm deep has an internal capacity of 2.000L at 18.0°C. It is completely filled with turpentine at 18.0°C. aluminum is 2.4 x 10Sec-1, and the average volume expansion coefficient for turpentine is 9.0 x 10tc-1.) turpentine and the aluminum cylinder are then slowly warmed together to 70.0C. (The average linear expansio (a) How much turpentine overflows? em (b) What is the volume of turpentine remaining in the cylinder at 70.0°C? (Give you answer to four significant figures.) cm (c) If the combination with this amount of turpentine is then cooled back to 18.0°C, how far below the cylinder's rim does the turpentine's surface recede? cm Additional Materials
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delta V = B ( linear expansion coefficient ) Vo ( delta T ) i think you will need to find the expansion of both the container and the liquid then subtrct the liquid height from the height of the cylider. then the rest is just repeating with dif #s
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