State the null and alternative hypothesis. H0: ≠, >, =, or < ____________ (Type an integers or decimals. Do not round) H1: ≠, >, ≤, <, ≥, or = __________ (Type an integers or decimals. Do not round) **Educational Content:****Hypothesis Testing on Cotinine Levels in Smokers vs. Nonsmokers**In this study, the claim is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL, which is found in nonsmokers. Cotinine serves as an important biomarker to measure exposure to nicotine. - **Sample Size:** The number of participants in the study is \( n = 778 \).- **Test Statistic:** The calculated t-value for the hypothesis test is \( t = 58.258 \).To reach a conclusion, use statistical technology to find the P-value, which will allow for determining if the observed result is statistically significant at the chosen significance level. The significance level (alpha) for this test is \( 0.10 \).**Task:**State the null and alternative hypotheses for the study:- **Null Hypothesis (\( H_0 \)):** - Representation: \(\mu \) - Value to compare: 2.84 - Hypothesis: The mean cotinine level for smokers is equal to 2.84 ng/mL.- **Alternative Hypothesis (\( H_1 \)):** - Representation: \(\mu \) - Value to compare: 2.84 - Hypothesis: The mean cotinine level for smokers is greater than 2.84 ng/mL.*(Note: Input either integers or decimals. Avoid rounding values.)* ### Statistical Analysis Exercise:1. **Test Statistic**: - The test statistic is represented as a blank input field. (Round to two decimal places as needed.)2. **P-Value**: - The P-value is represented as a blank input field. (Round to three decimal places as needed.)3. **Interpretation of P-Value**: - Based on the P-value, there is a dropdown menu providing options for the sufficiency of evidence. - This is followed by another dropdown menu to decide whether to reject or fail to reject the claim. - The claim in question is that smokers have a mean cotinine level greater than the level of 2.84 ng/mL found for nonsmokers.This exercise requires filling in statistical results to make an inference about cotinine levels in smokers compared to non-smokers.

The null and alternative hypothesis are H0: mue=2.84 H1: mue>2.84 The test statistic from the…

Answered: HoiH H₁: H (Type integers or decimals.…

Math

Statistics

HoiH H₁: H (Type integers or decimals. Do not round.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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