To test Ho: μ = 20 versus H₁ : µ< 20, a simple random sample of size n = 20 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d).Click here to view the t-Distribution Area in Right Tail.(a) If x = 18.4 and s=4.4, compute the test statistic.t= (Round to two decimal places as needed.)(b) Draw a t-distribution with the area that represents the P-value shaded. Which of the following graphs shows the correct shaded region?O A.B.A(c) Approximate the P-value. Choose the correct range for the P-value below.A. 0.20 < P-value < 0.25B. 0.15 < P-value <0.20OC. 0.10 < P-value < 0.15D. 0.05 < P-value < 0.100 0 0Qsa(d) If the researcher decides to test this hypothesis at the x = 0.05 level of significance, will the researcher reject the null hypothesis?A. The researcher will not reject the null hypothesis since the P-value is not less than α.B. The researcher will not reject the null hypothesis since the P-value is less than α.OC. The researcher will reject the null hypothesis since the P-value is not less than α.^

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Answered: Ho: μ=20 versus H₁: μ<20, a simple…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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F(144) Generation Y has been defined as those individuals who were born between 1981 and 1991. A 2010 survey by a credit counseling foundation found that 60% of the young adults in Generation Y pay their monthly bills on time. Suppose we take a random sample of 190 people from Generation Y. Question content area bottom Part 1 The distribution of p is a aproximately normal. Calculate the standard deviaiton of p. σp=enter your response here (Round to four decimal places as needed.) What is the probability that between 106 and 120 of them will pay their monthly bills on time? P(Between 106 and 120 of them will pay their monthly bills on time)=enter your response here (Round to four decimal places as needed.)
Cigarette Smoking A researcher found that a cigarette smoker smokes on average 32 cigarettes a day. She feels that this average is too high. She selected a random sample of 9 smokers and found that the mean number of cigarettes they smoked per day was 29. The sample standard deviation was 2.9. At α=0.01, is there enough evidence to support her claim? Assume that the population is approximately normally distributed. Use the critical value method and tables. Part: 0 / 5
Recreational Time A researcher wishes to see if there is a difference between the mean number of hours per week that a family with no children participates in recreational activities and a family with children participates in recreational activities. She selects two random samples and the data are shown. Use μ1 for the mean number of families with no children. At =α0.05, is there a difference between the means? Use the critical value method and tables. State the hypotheses and identify the claim. H0: Claim or not a Claim H1: Claim or not a claim Find the Critical Value(s): Round answer to at least 3 decimal places. Compute the test Value: Round the answer to at least 3 decimal places. Make the decision Summarize the results. There is or is not enough evidence to support the claim or reject the claim. X σ n No children 8.9 2.7 35 Children 10.5 2.8 35
Cigarette Smoking A researcher found that a cigarette smoker smokes on average 32 cigarettes a day. She feels that this average is too high. She selected a random sample of 9 smokers and found that the mean number of cigarettes they smoked per day was 29. The sample standard deviation was 2.9. At =α0.01, is there enough evidence to support her claim? Assume that the population is approximately normally distributed. Use the critical value method and tables.
A population of values has a normal distribution with μ=204.6μ=204.6 and σ=17σ=17. You intend to draw a random sample of size n=92n=92.Find P67, which is the score separating the bottom 67% scores from the top 33% scores.P67 (for single values) = IncorrectFind P67, which is the mean separating the bottom 67% means from the top 33% means.P67 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A population of values has a normal distribution with μ=106.2μ=106.2 and σ=61σ=61. You intend to draw a random sample of size n=85n=85.Find P93, which is the score separating the bottom 93% scores from the top 7% scores.P93 (for single values) = Find P93, which is the mean separating the bottom 93% means from the top 7% means.P93 (for sample means) = Enter your answers as numbers accurate to 1 decimal place.
A population of values has a normal distribution with μ=185.7μ=185.7 and σ=57.5σ=57.5. You intend to draw a random sample of size n=57n=57.Find P25, which is the score separating the bottom 25% scores from the top 75% scores.P25 (for single values) = Find P25, which is the mean separating the bottom 25% means from the top 75% means.P25 (for sample means) =
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Medical Operations The director of a medical hospital feels that her surgeons perform fewer operations per year than the national average of 211. She selected a random sample of 15 surgeons and found that the mean number of operations they performed was 210.6. The standard deviation of the sample was 3.8. Is there enough evidence to support the director's feelings at =α0.10? Assume that the population is approximately normally distributed. Use the critical value method and tables.a. State the hypotheses and identify the claim H0= (claim or not claim) H1= (claim or not claim) This hypothesis test is a (one tailed or two tailed) test Critical value(s)= t= (Reject or do not reject) the null hypothesis is there enough evidence to support the claim?
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