HO Br2 (1 equiv) 0° C

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Please draw the major organic product of the reaction 

The image shows a chemical reaction involving a benzene ring with a hydroxyl group (OH) and a side chain that appears to be a propyl group. This compound is reacting with molecular bromine (Br₂) under the condition of 0 degrees Celsius. The equation indicates that one equivalent of bromine is used. 

Here’s a breakdown of the components:

1. **Chemical Structure**: 
   - The benzene ring has a hydroxyl group (OH) attached, making it a phenol derivative.
   - There is a propyl group attached to the benzene ring, suggesting the compound is propylphenol.

2. **Reaction Conditions**: 
   - Bromine is used as a reagent.
   - The reaction is carried out at 0 degrees Celsius.

This type of reaction typically suggests an electrophilic aromatic substitution, where bromine could potentially substitute at an ortho or para position relative to the hydroxyl group, due to its activating and directing effects.
Transcribed Image Text:The image shows a chemical reaction involving a benzene ring with a hydroxyl group (OH) and a side chain that appears to be a propyl group. This compound is reacting with molecular bromine (Br₂) under the condition of 0 degrees Celsius. The equation indicates that one equivalent of bromine is used. Here’s a breakdown of the components: 1. **Chemical Structure**: - The benzene ring has a hydroxyl group (OH) attached, making it a phenol derivative. - There is a propyl group attached to the benzene ring, suggesting the compound is propylphenol. 2. **Reaction Conditions**: - Bromine is used as a reagent. - The reaction is carried out at 0 degrees Celsius. This type of reaction typically suggests an electrophilic aromatic substitution, where bromine could potentially substitute at an ortho or para position relative to the hydroxyl group, due to its activating and directing effects.
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The above reaction proceeds through a free radical mechanism as follows:

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