Hip surgery: In a sample of 124 hip surgeries of a certain type, the average surgery time was 137.1 minutes, with astandard deviation of 22.7 minutes.Part: 0 / 2Part 1 of 2Construct a 99.9% confidence interval for the mean surgery time for this procedure.Round the answers to one decimal place.A 99.9% confidence interval for the mean surgery time for this procedure isPart: 1 / 2Part 2 of 2<μ<If a 98% confidence interval were constructed with these data, would it be wider ornarrower than the interval constructed in part (a)? Explain.The new confidence interval would be (Choose one) than the interval constructed inpart (a).XXSŚ

Given information Sample size (n) = 124 Sample mean x̅ = 137.1 minutes Standard deviation (s) = 22.7…

Answered: Hip surgery: In a sample of 124 hip…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Part 1 of 3: A company was checking the number cars that parked in their lot each day and they estimated the population standard deviation was 1.6 cars. A sample of 45 days found that the mean number of cars was 13.2. Find 3-decimal small value of the 90% confidence interval of the mean. Part 2 of 3: Find 3-decimal large value of the 90% confidence interval of the mean. Part 3 of 3: What is the 3-decimal margin of error?
A sample of 30 randomly selected patients in a waiting room at a doctor’s office reported a mean wait time of 38.5 minutes. If the population standard deviation is 1.78 minutes, find a 95% confidence interval for the population mean wait time.
A random sample of 100 households was selected as part of a study on electricity usage, and the number of kilowatt-hours (kWh) was recorded for each household .The average usage was found to be 10.5 kWh. In a very large study in the previous year it was found that the standard deviation of the usage was 3.2 kWh. Assuming the standard deviation is unchanged and that the usage is normally distributed, calculate a 90% confidence interval for the mean usage (round to two decimals) a. (9.68 , 11.30) O b. (9.87 , 11.10) O c. (7.05 , 7.95) O d. None of these e. (9.97 , 11.00)
In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.5 and a standard deviation of 19.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µ
In a test of the effectiveness of garlic for lowering cholesterol, 47 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.7 and a standard deviation of 18.2. Construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean p? Question Viewer mg/dL < p< mg/dL (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits do not…
A small university is trying to monitor its electricity usage. For a random sample of 30 weekend days (Saturdays and Sundays), the student center used an average of 94.26 kilowatt hours (kWh) with standard deviation 43.29. For a random sample of 60 weekdays, (Monday - Friday), the student center used an average of 112.63 kWh with standard deviation 32.07. Construct a 95% confidence interval for the difference in mean electricity use at the student center between weekdays and weekend days. Use two decimal places in your margin of error. -6.80 to 43.54 kWh -4.61 to 41.35 kWh -3.38 to 40.51 kWh 0.12 to 36.62 kWh
For a random sample of 64 overweight men, the mean of the number of pounds that they were overweight was 30. The standard deviation of the population is 4.2 pounds. (a) Find the best point estimate for the average number of excess pounds for all overweight men. (b) Construct a 95% confidence interval of the mean of these pounds.
In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.1 and a standard deviation of 15.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? mg/dL mg/dL<µ< (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits contain 0, suggesting that the…
Multi-sensor data loggers were attached to free-ranging American alligators in a study conducted by Y. Watanabe for the article “Behavior of American Alligators Monitored by Multi-Sensor Data Loggers”. The margin of error for a sample of 68 dives was 31.2 seconds. Assume the population standard deviation is 100 seconds. If for the next study, a confidence interval for μ is to have a margin of error of 25 seconds and a confidence level of 99%, determine the required sample size. (Round up to the nearest whole number.)

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