Hint: The program has two functions: the main function and the m(int i) function. Step 1: Implement the m(int i) function to return the summation as shown in the formula for m(1) given in the description. Step 1.1: declare and initialize pi with 0 and declare and initialize sign with 1. Step 1.2: for each k from 1 to i, add sign / (2 * k-1.0) to pi. Note we are using 1.0 rather than 1 to obtain a louble result. Change sign using sign = -1 * sign. Step 1.3: return 4 * pi. Step 2: Implement the main function as follows: Step 2.1: Display the header of the table using iomanip. The header is "i m(i)". Step 2.2: Write a loop as follows: i is initially 1, display i and the result from invoking m(i) using iomanip. The result of m(i) is displayed with four digits after the decimal point. So, 4 should be displayed 4.0000. Step 2.3: Increment i by 100. Step 2.4: Continue the loop if i is less than 1000.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Write program in C++

Hint:
The program has two functions: the main function and the m(int i) function.
Step 1: Implement the m(int i) function to return the summation as shown in the formula for m(1) given in
the description.
Step 1.1: declare and initialize pi with 0 and declare and initialize sign with 1.
Step 1.2: for each k from 1 to i, add sign /(2* k-1.0) to pi. Note we are using 1.0 rather than 1 to obtain a
double result. Change sign using sign = -1 * sign.
Step 1.3: return 4 * pi.
Step 2: Implement the main function as follows:
Step 2.1: Display the header of the table using iomanip. The header is "i m(i)".
Step 2.2: Write a loop as follows: i is initially 1, display i and the result from invoking m(i) using iomanip.
The result of m(i) is displayed with four digits after the decimal point. So, 4 should be displayed 4.0000.
Step 2.3: Increment i by 100.
Step 2.4: Continue the loop if i is less than 1000.
Transcribed Image Text:Hint: The program has two functions: the main function and the m(int i) function. Step 1: Implement the m(int i) function to return the summation as shown in the formula for m(1) given in the description. Step 1.1: declare and initialize pi with 0 and declare and initialize sign with 1. Step 1.2: for each k from 1 to i, add sign /(2* k-1.0) to pi. Note we are using 1.0 rather than 1 to obtain a double result. Change sign using sign = -1 * sign. Step 1.3: return 4 * pi. Step 2: Implement the main function as follows: Step 2.1: Display the header of the table using iomanip. The header is "i m(i)". Step 2.2: Write a loop as follows: i is initially 1, display i and the result from invoking m(i) using iomanip. The result of m(i) is displayed with four digits after the decimal point. So, 4 should be displayed 4.0000. Step 2.3: Increment i by 100. Step 2.4: Continue the loop if i is less than 1000.
*6.13 (Estimate π) can be computed using the following summation:
m (i) = 4 (1
► = 4 (1 − / + } }
Sample Run for Exercise06_13.cpp
Execution Result:
command>Exercise06_13
m(i)
4.0000
3.1515
3.1466
i
1
101
201
301
401
501
601
701
801
901
Write a function that returns m(i) for a given i and write a test program that
displays the following table:
command>
3.1449
3.1441
3.1436
3.1433
=/=/2 +
3.1430
3.1428
3.1427
(−1)¹+¹
+ + 2i-1
Transcribed Image Text:*6.13 (Estimate π) can be computed using the following summation: m (i) = 4 (1 ► = 4 (1 − / + } } Sample Run for Exercise06_13.cpp Execution Result: command>Exercise06_13 m(i) 4.0000 3.1515 3.1466 i 1 101 201 301 401 501 601 701 801 901 Write a function that returns m(i) for a given i and write a test program that displays the following table: command> 3.1449 3.1441 3.1436 3.1433 =/=/2 + 3.1430 3.1428 3.1427 (−1)¹+¹ + + 2i-1
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