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Hii, I asked this question but may I ask how to get 1.1547? thank you

Hii, I asked this question but may I ask how to get 1.1547? thank you

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hii, I asked this question but may I ask how to get 1.1547? thank you
5:43 ← ANSWERED Friday, Nov 11, 2022 ENGINEERING MECHANICAL-ENGINEERING Given the trust below and a force P applied downwards at Point D, determine the member forces EC and CD using Method of Joints urgentt thank you Expert Answer Step1 a) Given: A force P applied downward - To Find: The member forces of iniute ? at EC & CD √x point D using DO 8
Transcribed Image Text:5:43 ← ANSWERED Friday, Nov 11, 2022 ENGINEERING MECHANICAL-ENGINEERING Given the trust below and a force P applied downwards at Point D, determine the member forces EC and CD using Method of Joints urgentt thank you Expert Answer Step1 a) Given: A force P applied downward - To Find: The member forces of iniute ? at EC & CD √x point D using DO 8
5:43 个 Step2 b) - Draw > Solution: Using Method CD c0560' ED Draw BC CE Singo' 4 EC CD + CD Sin60 ECC0168 Answers: D 43 60' P C B 43 FBD of joint D. + CDCOS 60' CD Sin60 CD Member Ec 43 FBD of joint c. 43 20 of joints. 43 4 C Force (1.1547) P (1.1547) P 60 IF 20 CD sin 60 D P (++); = = P + CD = (1.1547) P (Tension) EF co co +), EC sin 60 = CD sin60" EC = CD "EC = (1-1547) P [Compression) Nature of Force Tension Compression, Was this solution √x DO
Transcribed Image Text:5:43 个 Step2 b) - Draw > Solution: Using Method CD c0560' ED Draw BC CE Singo' 4 EC CD + CD Sin60 ECC0168 Answers: D 43 60' P C B 43 FBD of joint D. + CDCOS 60' CD Sin60 CD Member Ec 43 FBD of joint c. 43 20 of joints. 43 4 C Force (1.1547) P (1.1547) P 60 IF 20 CD sin 60 D P (++); = = P + CD = (1.1547) P (Tension) EF co co +), EC sin 60 = CD sin60" EC = CD "EC = (1-1547) P [Compression) Nature of Force Tension Compression, Was this solution √x DO
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