Higher Order Derivatives Uses: acceleration, concavity Position: s (t) Second Derivative: Velocity: v (t) = s' (t) %3D d ( dy dæ ( dæ dy also f", y" dæ? Acceleration: a (t) = v' (t) = s" (t) 1. The height in feet at any time t (in seconds) of a particle thrown vertically is h (t) = –16t² + 256t. a. Find the particle's average velocity for the first 3 second of travel. b. How fast is the particle traveling 6 seconds after it is thrown and how high is it? c. When does the article reach its maximum height and what is that maximum height? d. What is the acceleration of the particle at t = 5 seconds?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Higher Order Derivatives
Uses: acceleration, concavity
Position: s (t)
Second Derivative:
Velocity: v (t) = s' (t)
dy
also f", y"
dx?
d
dy
Acceleration: a (t) = v' (t) = s" (t)
dx
dx
1. The height in feet at any time t (in seconds) of a particle thrown vertically is h (t)
= -16t? + 256t.
a. Find the particle's average velocity for the first 3 second of travel.
b. How fast is the particle traveling 6 seconds after it is thrown and how high is it?
c. When does the article reach its maximum height and what is that maximum height?
d. What is the acceleration of the particle at t = 5 seconds?
Transcribed Image Text:Higher Order Derivatives Uses: acceleration, concavity Position: s (t) Second Derivative: Velocity: v (t) = s' (t) dy also f", y" dx? d dy Acceleration: a (t) = v' (t) = s" (t) dx dx 1. The height in feet at any time t (in seconds) of a particle thrown vertically is h (t) = -16t? + 256t. a. Find the particle's average velocity for the first 3 second of travel. b. How fast is the particle traveling 6 seconds after it is thrown and how high is it? c. When does the article reach its maximum height and what is that maximum height? d. What is the acceleration of the particle at t = 5 seconds?
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