High-rent district: The mean monthly rent for a one-bedroom apartment without a doorman in Manhattan is $2663. Assume the standard deviation is $506. A real estate firm samples 106 apartments. Use Excel. Part 1 of 5 (a) What is the probability that the sample mean rent is greater than $2733? Round the answer to at least four decimal places. The probability that the sample mean rent is greater than $2733 is 0772 Alternate Answer: The probability that the sample mean rent is greater than $2733 is 0,0772. Part 2 of 5 (b) What is the probability that the sample mean rent is between $2500 and $2575? Round the answer to at least four decimal places. The probability that the sample mean rent is between $2500 and $2575 is .0367 Part 3 of 5 (c) Find the 90 percentile of the sample mean. Round the answer to at least two decimal places. The 90th percentile of the sample mean rent is $2726.01 Part 4 of 5

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Do you think it would be unusual for an individual apartment to have a rent greater than $2690?
High-rent district: The mean monthly rent for a one-bedroom
apartment without a doorman in Manhattan is $2663. Assume the
standard deviation is $506. A real estate firm samples 106 apartments. Use
Excel.
Part 1 of 5
(a) What is the probability that the sample mean rent is greater than
$2733? Round the answer to at least four decimal places.
The probability that the sample mean rent is greater than $2733 is 0772
Alternate Answer:
The probability that the sample mean rent is greater than $2733 is
0,0772.
Part 2 of 5
(b) What is the probability that the sample mean rent is between
$2500 and $2575? Round the answer to at least four decimal places.
The probability that the sample mean rent is between $2500 and $2575 is .0367
Part 3 of 5
(c) Find the 90th percentile of the sample mean. Round the answer to
at least two decimal places.
The 90th percentile of the sample mean rent is s 2726.01
Part 4 of 5
(d) Would it be unusual if the sample mean were greater than $2690?
Round the answer to at least four decimal places.
No
than $2690 is 2912.
Part: 4/5
because the probability that the sample mean is greater
Part 5 of 5
(e) Do you think it would be unusual for an individual apartment to
have a rent greater than $2690? Explain. Assume the variable is
normally distributed. Round the answer to at least four decimal
places.
(Choose one) because the probability that an apartment has a rent
greater than $2690 is.
Transcribed Image Text:High-rent district: The mean monthly rent for a one-bedroom apartment without a doorman in Manhattan is $2663. Assume the standard deviation is $506. A real estate firm samples 106 apartments. Use Excel. Part 1 of 5 (a) What is the probability that the sample mean rent is greater than $2733? Round the answer to at least four decimal places. The probability that the sample mean rent is greater than $2733 is 0772 Alternate Answer: The probability that the sample mean rent is greater than $2733 is 0,0772. Part 2 of 5 (b) What is the probability that the sample mean rent is between $2500 and $2575? Round the answer to at least four decimal places. The probability that the sample mean rent is between $2500 and $2575 is .0367 Part 3 of 5 (c) Find the 90th percentile of the sample mean. Round the answer to at least two decimal places. The 90th percentile of the sample mean rent is s 2726.01 Part 4 of 5 (d) Would it be unusual if the sample mean were greater than $2690? Round the answer to at least four decimal places. No than $2690 is 2912. Part: 4/5 because the probability that the sample mean is greater Part 5 of 5 (e) Do you think it would be unusual for an individual apartment to have a rent greater than $2690? Explain. Assume the variable is normally distributed. Round the answer to at least four decimal places. (Choose one) because the probability that an apartment has a rent greater than $2690 is.
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