Let X = (Y,Z) be the fair dice roll with E(Y) = {1,...,6} with PY (y) = 1/6, and Z being an independent fair coin toss with E(Z) = {0,1} and PZ(z) = 1/2. What is the probability of the event that z + y = 2? What is PZ|Y (1|6)?

Let X = (Y,Z) be the fair dice roll with E(Y) = {1,...,6} with PY (y) = 1/6, and Z being an independent fair coin toss with E(Z) = {0,1} and PZ(z) = 1/2. What is the probability of the event that z + y = 2? What is PZ|Y (1|6)?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Let X = (Y,Z) be the fair dice roll with E(Y) = {1,...,6} with PY (y) = 1/6, and Z being an independent fair coin toss with E(Z) = {0,1} and PZ(z) = 1/2.

What is the probability of the event that z + y = 2?

What is PZ|Y (1|6)?

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Hi sorry for the first part I don't get it I was expecting the result to be 2 but you show 1/6. Which looks like to be incorrect. I was expecting something like that

⅙+⅙+⅙ = 3/6

½+½+½= 3/2

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