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Hi! My professor wrote this but I dont really understand why the angle was not really the 30 degrees, I understand the geometry and the equation, but I need help with the thought process behind it. Thank you!

Hi! My professor wrote this but I dont really understand why the angle was not really the 30 degrees, I understand the geometry and the equation, but I need help with the thought process behind it. Thank you!

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Hi! My professor wrote this but I dont really understand why the angle was not really the 30 degrees, I understand the geometry and the equation, but I need help with the thought process behind it. Thank you!

10. B=40x10³³ + I = 8A N = 80 A = 0,12m ² 0 = 30° loop? 11. A) The current will go clockwise The current will go counter-clockwise The current will be zero because the inner loop is not connected to a power supply D) The current will be zero because the inner loop is not moving 0.34 Nm 1.5 Nm 2.5 Nm D) 2.7 Nm 3.1 Nm A) B The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped turns each carrying a current I. The magnetic field in the region is 40 mT, pointing in the ✰ -direction. The loop can turn about the y axis. If = 30°, a = 0.40 m, b = 0.30 m, and /= 8.0 A, what is the magnitude of the torque exerted on the loop? r=N·I·A·B· sino (A) B = BY B = ie in the same plane as shown in the figure. If the current I in the outer ncreasing with time, what is true about the current in the in the inner Hol ATC Hol 4TC T = (80) (8A) (0.12m²) (40 x 10²³7) •sen 30° ↑ Goo = 1.536 №.m ol dx S-00x²49 You want to use Biot-Savart's law to calculate the magnetic field at a point y = 3, created by an infinitely long wire stretched along the x-axis, and carrying a current I. How should you set up the integral? -3 dy So x² + y² cew B I B A=6.4)(0-30m) A = 0.12m² olign w/ B ور) dB = M. Ids x 1 4.π r² ● 2= √√x²+9
Transcribed Image Text:10. B=40x10³³ + I = 8A N = 80 A = 0,12m ² 0 = 30° loop? 11. A) The current will go clockwise The current will go counter-clockwise The current will be zero because the inner loop is not connected to a power supply D) The current will be zero because the inner loop is not moving 0.34 Nm 1.5 Nm 2.5 Nm D) 2.7 Nm 3.1 Nm A) B The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped turns each carrying a current I. The magnetic field in the region is 40 mT, pointing in the ✰ -direction. The loop can turn about the y axis. If = 30°, a = 0.40 m, b = 0.30 m, and /= 8.0 A, what is the magnitude of the torque exerted on the loop? r=N·I·A·B· sino (A) B = BY B = ie in the same plane as shown in the figure. If the current I in the outer ncreasing with time, what is true about the current in the in the inner Hol ATC Hol 4TC T = (80) (8A) (0.12m²) (40 x 10²³7) •sen 30° ↑ Goo = 1.536 №.m ol dx S-00x²49 You want to use Biot-Savart's law to calculate the magnetic field at a point y = 3, created by an infinitely long wire stretched along the x-axis, and carrying a current I. How should you set up the integral? -3 dy So x² + y² cew B I B A=6.4)(0-30m) A = 0.12m² olign w/ B ور) dB = M. Ids x 1 4.π r² ● 2= √√x²+9
10. The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped turns each carrying a current /. The magnetic field in the region is 40 mT, pointing in the direction. The loop can turn about the y axis. If = 30°, a = 0.40 m, b = 0.30 m, and /= 8.0 A, what is the magnitude of the torque exerted on the loop? -not 300⁰° but 60° (or 120°), y T= NIAB SIG☺ = 80·8·0,4-0.3 × 40×16³ sinboo 2,66 A) 0.34 Nm B) 1.5 Nm C) 2.5 Nm 2.7 Nm 3.1 Nm = 2 I 2 (view from above 60 300 X Tangle between M and B = 60° (or 120⁰)
Transcribed Image Text:10. The figure shows the orientation of a rectangular loop consisting of 80 closely wrapped turns each carrying a current /. The magnetic field in the region is 40 mT, pointing in the direction. The loop can turn about the y axis. If = 30°, a = 0.40 m, b = 0.30 m, and /= 8.0 A, what is the magnitude of the torque exerted on the loop? -not 300⁰° but 60° (or 120°), y T= NIAB SIG☺ = 80·8·0,4-0.3 × 40×16³ sinboo 2,66 A) 0.34 Nm B) 1.5 Nm C) 2.5 Nm 2.7 Nm 3.1 Nm = 2 I 2 (view from above 60 300 X Tangle between M and B = 60° (or 120⁰)
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