Hi I know that you can’t answer all questions. Can you just answer question 21 please.
Hi I know that you can’t answer all questions. Can you just answer question 21 please.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Hi I know that you can’t answer all questions. Can you just answer question 21 please.
![Use the following scenario to answer questions 18-25:
Battery life of MP3 players is of great concern to customers. A consumer group has
tested four brands of such players to determine the battery life. Samples of players of
each brand were fully charged and left to run at medium volume until the battery died.
The number of hours that each player ran was recorded. The following graphs and
tables from the analysis of the data are provided:
34
32
30-
28-
e26
26-
24-
22-
20-
18-
16
Brand A
Brand B
Brand C
Brand D
Brands
Means and Std Deviations
Brand Number Mean
Std Dev
A
14
24.63 4.22
В
15
27.71 2.74
14
24.87 2.95
D
11
27.32 3.06
Analysis of Variance
Source DF
F Ratio P-value
Sum of Squares Mean Square
107.022
10.865
Brands 3
35.674
**
Егror 50
543.273
Total 53
650.295
18.
What conclusion might one draw by looking at the side-by side boxplots?
The ANOVA assumption of Normality of the data is satisfied.
The population means certainly are different.
A)
B)
C)
There is insufficient data to justify reaching any conclusion here.
There is different variability from brand-to-brand but not enough difference to
raise concern about the common variance ANOVA assumption.
The consumer group should look at the Normal quantile plot to verify the
common variance assumption.
D)
E)
Answer:
How many degrees of freedom are there for Error (DFE) and what is the value
of the MSE?
19.
A)
DFE = 51: MSE = 10.65
B)
DFE = 49: MSE = 11.09
C)
DFE - 51: MSE = 10.87
D)
DFE = 50: MSE = 12.27
E)
DFE = 50: MSE = 10.87
Answer:
20.
To test the ANOVA null hypothesis Ho: = 4: = 2]= H, , what are the test
statistic and its associated P-value?
A)
F(3, 50) = 3.28; 0.01 <P<0.025
B)
F(3, 50) = 2.91; 0.02 < P<0.05
F(4, 49) = 3.28; 0.01 <P<0.025
F(3, 50) = 3.28; 0.025 <P< 0.05
F(4, 50) - 2.91; 0.025 < P<0.0s
C)
D)
E)
Answer:
Bonus Points
21.
What conclusion might you reach based on these analyses?
There is no evidence to suggest that the null hypothesis should be rejected.
There is evidence to support the conclusion that all the population means are
different.
A)
B)
C)
There is sufficient evidence to conclude that the sample means are not equal.
There is sufficient evidence to conclude that not all the population means are
equal.
It would be dangerous to conclude anything because the sample sizes are small
and some of the ANOVA assumptions are not satisfied.
D)
E)
Answer:
22.
Because one of the brands of MP3 players (Brand B) is known to be the most
HTH
HOH](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7829d723-61c8-4c89-86b3-ca3adaa41272%2Fd7c5620c-fc9c-4e5a-813e-530798e1235a%2F3dhxp9i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Use the following scenario to answer questions 18-25:
Battery life of MP3 players is of great concern to customers. A consumer group has
tested four brands of such players to determine the battery life. Samples of players of
each brand were fully charged and left to run at medium volume until the battery died.
The number of hours that each player ran was recorded. The following graphs and
tables from the analysis of the data are provided:
34
32
30-
28-
e26
26-
24-
22-
20-
18-
16
Brand A
Brand B
Brand C
Brand D
Brands
Means and Std Deviations
Brand Number Mean
Std Dev
A
14
24.63 4.22
В
15
27.71 2.74
14
24.87 2.95
D
11
27.32 3.06
Analysis of Variance
Source DF
F Ratio P-value
Sum of Squares Mean Square
107.022
10.865
Brands 3
35.674
**
Егror 50
543.273
Total 53
650.295
18.
What conclusion might one draw by looking at the side-by side boxplots?
The ANOVA assumption of Normality of the data is satisfied.
The population means certainly are different.
A)
B)
C)
There is insufficient data to justify reaching any conclusion here.
There is different variability from brand-to-brand but not enough difference to
raise concern about the common variance ANOVA assumption.
The consumer group should look at the Normal quantile plot to verify the
common variance assumption.
D)
E)
Answer:
How many degrees of freedom are there for Error (DFE) and what is the value
of the MSE?
19.
A)
DFE = 51: MSE = 10.65
B)
DFE = 49: MSE = 11.09
C)
DFE - 51: MSE = 10.87
D)
DFE = 50: MSE = 12.27
E)
DFE = 50: MSE = 10.87
Answer:
20.
To test the ANOVA null hypothesis Ho: = 4: = 2]= H, , what are the test
statistic and its associated P-value?
A)
F(3, 50) = 3.28; 0.01 <P<0.025
B)
F(3, 50) = 2.91; 0.02 < P<0.05
F(4, 49) = 3.28; 0.01 <P<0.025
F(3, 50) = 3.28; 0.025 <P< 0.05
F(4, 50) - 2.91; 0.025 < P<0.0s
C)
D)
E)
Answer:
Bonus Points
21.
What conclusion might you reach based on these analyses?
There is no evidence to suggest that the null hypothesis should be rejected.
There is evidence to support the conclusion that all the population means are
different.
A)
B)
C)
There is sufficient evidence to conclude that the sample means are not equal.
There is sufficient evidence to conclude that not all the population means are
equal.
It would be dangerous to conclude anything because the sample sizes are small
and some of the ANOVA assumptions are not satisfied.
D)
E)
Answer:
22.
Because one of the brands of MP3 players (Brand B) is known to be the most
HTH
HOH
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