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) Here we have find Litezt sinst} NOW, L{ sinot} g+62 - 3(4), say s436 So, L{t sindt} = (-1)' ges) as %3D 8436 ス (84 34) = f(s), say rie Lstsinst} %3D 12s %3D By the first romslation theorem, 1feat t sinst} = F(s-2) 12(3-2).[:f5436)) 12s 12s-24 いー4+4+34j 125-24 Therefore, L{teztsinst} = 12s-24

) Here we have find Litezt sinst} NOW, L{ sinot} g+62 - 3(4), say s436 So, L{t sindt} = (-1)' ges) as %3D 8436 ス (84 34) = f(s), say rie Lstsinst} %3D 12s %3D By the first romslation theorem, 1feat t sinst} = F(s-2) 12(3-2).[:f5436)) 12s 12s-24 いー4+4+34j 125-24 Therefore, L{teztsinst} = 12s-24

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(6) can you explain in DETAIL how did you come up with this solution coz i'm going to make a script out of it
) Here we hove find L{te?t sinat} NoW, L sinct}= s+62 =g(s), say s436 So, L{t sinot} = E1)' d ges) ds' も436 2s] (4 34) lie Lstsinsts 12s (s), say By the first amslation theorem, t sinst} = f(s-2) 12(3-2) 1{eat 12s () ど43) こ 12s-24 いー4+リ+34) 125-24 Therefore, 2s-29 Lfteztsinst} =
Transcribed Image Text:) Here we hove find L{te?t sinat} NoW, L sinct}= s+62 =g(s), say s436 So, L{t sinot} = E1)' d ges) ds' も436 2s] (4 34) lie Lstsinsts 12s (s), say By the first amslation theorem, t sinst} = f(s-2) 12(3-2) 1{eat 12s () ど43) こ 12s-24 いー4+リ+34) 125-24 Therefore, 2s-29 Lfteztsinst} =
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