Here the 5x²+7y=35 Differentiate wir.t 'n we have 21071 1101 9 ㅠ → dy Jn T →) dy dn T +14y dy 52 - 54 3 17 7y ..The equ" of the tangent at (*17) (xg) (Y-y). 377 (x-x) -5X+5xv 7 7 Yy - 7y² = x 7 5xx + 7 Yg = 5n²+ry 2 35 (-) which x 5 x x + 7 xy parallel is 3x +47-12=0 21= = 2 C - 1 ту 1 1 7 4 to the st. Line 4 2 35 38 103 14y. Sm 35 =72 42X3 48 352 5 y=-35 x 1 y = - 31/12 the tangent - नम → 3* + 3x +47 +12=0. The equation of the за 3x+ay+12= 9 ... Equn of S* ( - 2 ) + 7 Y ( - §/3) = 35 Sx 크 ⇒-105X140X = 35x12 -3x - 4y = 12 tangent (Ans 5/35 връе ло s
Here the 5x²+7y=35 Differentiate wir.t 'n we have 21071 1101 9 ㅠ → dy Jn T →) dy dn T +14y dy 52 - 54 3 17 7y ..The equ" of the tangent at (*17) (xg) (Y-y). 377 (x-x) -5X+5xv 7 7 Yy - 7y² = x 7 5xx + 7 Yg = 5n²+ry 2 35 (-) which x 5 x x + 7 xy parallel is 3x +47-12=0 21= = 2 C - 1 ту 1 1 7 4 to the st. Line 4 2 35 38 103 14y. Sm 35 =72 42X3 48 352 5 y=-35 x 1 y = - 31/12 the tangent - नम → 3* + 3x +47 +12=0. The equation of the за 3x+ay+12= 9 ... Equn of S* ( - 2 ) + 7 Y ( - §/3) = 35 Sx 크 ⇒-105X140X = 35x12 -3x - 4y = 12 tangent (Ans 5/35 връе ло s
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Here the equation of the ellipse is
5x² + 7y = 35
Differentiate wir.t 'n we have
→ dy
dn
→ dy
J =
5"
ту
... The equ" of the tangent at (248)
10m +147 day=0
20
T
5xx+5xv
→ 7Yу-7у*.
75xx+7Y7 = 3x²+xy L
2
35
ī
25 Xx +7
+7Yy
is parallel to the
ㅋ
2
→
5म
(Y - 7) = - 3
77
52 -
-
3
5/3
17
1071
147.
AY
to the st. line
10x1
35
5/d 1/4
12
38
35
=12
4
7
21=
4
st. Line 3x +
- 3x 48=1
=12
zy
4
(1) which
3x + 4y - 12=0.
Equin of the tangent
S* ( - 2 ) + 7Y (-¾/3) = 35
7 -105X140Y-
7
35X12
-
3x +47 +12=0
The equation of the
3x+ay+12=0 (Ane)
5
y=-35 x 1
38
*
3523
y = -5/23
torgent
nt is](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8a2fcb2e-1793-4f3b-8ae9-1e7d9c23ae43%2F1239465e-103c-4b59-8c02-2f4b6dcc03ec%2F6gdiw7x_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Here the equation of the ellipse is
5x² + 7y = 35
Differentiate wir.t 'n we have
→ dy
dn
→ dy
J =
5"
ту
... The equ" of the tangent at (248)
10m +147 day=0
20
T
5xx+5xv
→ 7Yу-7у*.
75xx+7Y7 = 3x²+xy L
2
35
ī
25 Xx +7
+7Yy
is parallel to the
ㅋ
2
→
5म
(Y - 7) = - 3
77
52 -
-
3
5/3
17
1071
147.
AY
to the st. line
10x1
35
5/d 1/4
12
38
35
=12
4
7
21=
4
st. Line 3x +
- 3x 48=1
=12
zy
4
(1) which
3x + 4y - 12=0.
Equin of the tangent
S* ( - 2 ) + 7Y (-¾/3) = 35
7 -105X140Y-
7
35X12
-
3x +47 +12=0
The equation of the
3x+ay+12=0 (Ane)
5
y=-35 x 1
38
*
3523
y = -5/23
torgent
nt is
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