Here is the question for a Calc 1 online class: The position function s(t) = -4.9t^2 + 300 gives the height (ft) of an object falling from 300 feet. The velocity function is given as a limit as x approaches 0 v(t)=s(t+Δt) -s(t)/Δt. 1. Determine the velocity of an object as a function of time by evaluting the limit.
Rate of Change
The relation between two quantities which displays how much greater one quantity is than another is called ratio.
Slope
The change in the vertical distances is known as the rise and the change in the horizontal distances is known as the run. So, the rise divided by run is nothing but a slope value. It is calculated with simple algebraic equations as:
Here is the question for a Calc 1 online class:
The position function s(t) = -4.9t^2 + 300 gives the height (ft) of an object falling from 300 feet. The velocity function is given as a limit as x approaches 0 v(t)=s(t+Δt) -s(t)/Δt.
1. Determine the velocity of an object as a function of time by evaluting the limit.
2. Determine the velocity of the object right before the object makes contact with the ground
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