Here is the optimal tableau for a Max LP z x1 X3 81 82 83 rhs 1 0 0 0 10 10 280 0 0 0 1 5/2 -8 24 0 0 -2 1 0 3/2 -4 8 0 1 1.25 0 0 -0.5 1.5 2 1. For the B-matrix method what is the first row of B-¹ x2 5 -2 column1 enter fractions like so 7/2 with no extra spaces 2. After calculating B (i.e. the inverse of B-¹) the original columna has values: row1 = b1 column2 = ; b2= row2 = 3. Using B-matrix method, the original rhs vector b had these coordinate values: ; and b3 = column3 = Hint: remember new rhs equals B-¹ times original rhs, so ...? row3 =
Here is the optimal tableau for a Max LP z x1 X3 81 82 83 rhs 1 0 0 0 10 10 280 0 0 0 1 5/2 -8 24 0 0 -2 1 0 3/2 -4 8 0 1 1.25 0 0 -0.5 1.5 2 1. For the B-matrix method what is the first row of B-¹ x2 5 -2 column1 enter fractions like so 7/2 with no extra spaces 2. After calculating B (i.e. the inverse of B-¹) the original columna has values: row1 = b1 column2 = ; b2= row2 = 3. Using B-matrix method, the original rhs vector b had these coordinate values: ; and b3 = column3 = Hint: remember new rhs equals B-¹ times original rhs, so ...? row3 =
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:Here is the optimal tableau for a Max LP
x1
X3 $1
$2 83
rhs
1
0
0 0
10 10 280
0
0
0 1
5/2
-8
24
0
0
-2 1 0
3/2 -4
8
0 1
1.25 0 0 0.5 1.5 2
1. For the B-matrix method what is the first row of B-1
N
X2
5
-2
column1 =
enter fractions like so 7/2 with no extra spaces
2. After calculating B (i.e. the inverse of B-¹) the original
column ahas values: row1 =
b1 =
column2
; b2
row2 =
3. Using B-matrix method, the original rhs vector b had these coordinate values:
; and b3
column3 =
Hint: remember new rhs equals B-¹ times original rhs, so...?
row3 =
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