Here is an integral: ∫(t + 1)/(√1 - t2) dt, where 0 < t < 1 what option gives the integral obtained by using the substituation u = arccos t? 1. ∫(- cos u - 1) du 2. ∫-(-cos u - 1)/(sin u) du 3. ∫-(-cos u - 1)/(sin u) dt 4. ∫-(t + 1)/(√1 - t2) du
Here is an integral: ∫(t + 1)/(√1 - t2) dt, where 0 < t < 1 what option gives the integral obtained by using the substituation u = arccos t? 1. ∫(- cos u - 1) du 2. ∫-(-cos u - 1)/(sin u) du 3. ∫-(-cos u - 1)/(sin u) dt 4. ∫-(t + 1)/(√1 - t2) du
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Here is an
∫(t + 1)/(√1 - t2) dt, where 0 < t < 1
what option gives the integral obtained by using the substituation u = arccos t?
1. ∫(- cos u - 1) du
2. ∫-(-cos u - 1)/(sin u) du
3. ∫-(-cos u - 1)/(sin u) dt
4. ∫-(t + 1)/(√1 - t2) du
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