Here is an improved version of our program for finding the roots of a quadratic.Try it with some different values of a2, a1, and a0.# program spuRs/resources/scripts/quad2.r# find the zeros of a2*x^2 + a1*x + a0 = 0#clear the workspacerm (list=1s())# inputa2 < 1al <- 4a0 < - 5# calculate the discriminantdiscrim <- al^2 - 4*a2*a0# calculate the roots depending on the value of the discriminantif (discrim > 0) {roots <-c( (-al+sqrt (a1^2 - 4*a2*a0))/(2*a2),sqrt (a1^2 4*a2*a0))/(2*a2) )} else {}(-a1if (discrim = : 0) {} else {}roots <-a1/(2*a2)-roots <-c()# outputshow (roots)

Here is an improved version of our program for finding the roots of a quadratic. Try it with some different values of a2, a1, and a0. # program spuRs/resources/scripts/quad2.r # find the zeros of a2*x^2 + a1*x + a0 = 0 # clear the workspace rm (list=1s()) #input a2 <- 1 a1 <- 4 a0 <- 5 # calculate the discriminant discrim <- a1^2 - 4*a2*a0 # calculate the roots depending on the value of the discriminant if (discrim > 0) { roots <-c( (-a1 + sqrt (a1^2 - 4*a2*a0))/(2*a2), (-a1 sqrt (a1^2-4*a2*a0))/(2*a2) ) } else { if (discrim == 0) { } else { } roots < -a1/(2*a2) - roots <-c() # output show (roots)

Here is an improved version of our program for finding the roots of a quadratic. Try it with some different values of a2, a1, and a0. # program spuRs/resources/scripts/quad2.r # find the zeros of a2x^2 + a1x + a0 = 0 # clear the workspace rm (list=1s()) #input a2 <- 1 a1 <- 4 a0 <- 5 # calculate the discriminant discrim <- a1^2 - 4a2a0 # calculate the roots depending on the value of the discriminant if (discrim > 0) { roots <-c( (-a1 + sqrt (a1^2 - 4a2a0))/(2a2), (-a1 sqrt (a1^2-4a2a0))/(2a2) ) } else { if (discrim == 0) { } else { } roots < -a1/(2*a2) - roots <-c() # output show (roots)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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