Here are summary statistics for the weights of Pepsi in randomly selected​ cans: n​=36,x=0.82407 ​lb, s=0.00568 lb. Use a confidence level of ​90% to complete parts​ (a) through​ (d) below. a. Identify the critical value to/2 used for finding the margin of error. tx/2 = (Round to two decimal places as needed.) b. Find the margin of error. E= lb (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ. Ib

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Here are summary statistics for the weights of Pepsi in randomly selected​ cans: n​=36,x=0.82407 ​lb, s=0.00568 lb. Use a confidence level of ​90% to complete parts​ (a) through​ (d) below. a. Identify the critical value to/2 used for finding the margin of error. tx/2 = (Round to two decimal places as needed.) b. Find the margin of error. E= lb (Round to five decimal places as needed.) c. Find the confidence interval estimate of μ. Ib<u<{ lb (Round to five decimal places as needed.) d. Write a brief statement that interprets the confidence interval.

**Summary Statistics for Pepsi Can Weights**

Here are the summary statistics for the weights of Pepsi in randomly selected cans:

- Sample size (n): 36
- Mean weight (\( \bar{x} \)): 0.82407 lb
- Standard deviation (s): 0.00568 lb

Use a confidence level of 90% to complete parts (a) through (d) below.

---

**a. Critical Value for Margin of Error**

Identify the critical value \( t_{\alpha/2} \) used for finding the margin of error.

\( t_{\alpha/2} = \) [ ]

*Note: Round to two decimal places as needed.*
Transcribed Image Text:**Summary Statistics for Pepsi Can Weights** Here are the summary statistics for the weights of Pepsi in randomly selected cans: - Sample size (n): 36 - Mean weight (\( \bar{x} \)): 0.82407 lb - Standard deviation (s): 0.00568 lb Use a confidence level of 90% to complete parts (a) through (d) below. --- **a. Critical Value for Margin of Error** Identify the critical value \( t_{\alpha/2} \) used for finding the margin of error. \( t_{\alpha/2} = \) [ ] *Note: Round to two decimal places as needed.*
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