Here are summary statistics for the weights of Pepsi in randomly selected cans: n = 36, x̄ = 0.82408 lb, s = 0.00568 lb. Use a confidence level of 95% to complete parts (a) through (d) below.a. Identify the critical value t(α/2) used for finding the margin of error.t(α/2) = [ ] (Round to two decimal places as needed.)b. Find the margin of error.E = [ ] lb (Round to five decimal places as needed.)c. Find the confidence interval estimate of μ.[ ] lb < μ < [ ] lb (Round to five decimal places as needed.)d. Write a brief statement that interprets the confidence interval. Choose the correct answer below.- A. One has 95% confidence that the sample mean weight of Pepsi in a can is equal to the population mean weight of Pepsi in a can.- B. Approximately 95% of sample mean weights of Pepsi in a can will fall between the lower bound and the upper bound.- C. There is a 95% chance that the true value of the population mean weight of Pepsi in a can will fall between the lower bound and the upper bound.- D. One has 95% confidence that the interval from the lower bound to the upper bound contains the true value of the population mean weight of Pepsi in a can.

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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