Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82407 lb, s=0.00568 lb. Use a confidence level of 95% to complete parts (a) through (d) below.
Here are summary statistics for the weights of Pepsi in randomly selected cans: n=36, x=0.82407 lb, s=0.00568 lb. Use a confidence level of 95% to complete parts (a) through (d) below.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:<
Here are summary statistics for the weights of Pepsi in randomly selected cans: n = 36, x=0.82407 lb,
s=0.00568 lb. Use a confidence level of 95% to complete parts (a) through (d) below.
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Transcribed Image Text:a. Identify the critical value to/2 used for finding the margin of error.
tx/2 =
(Round to two decimal places as needed.)
b. Find the margin of error.
E=
lb
(Round to five decimal places as needed.)
c. Find the confidence interval estimate of μ.
Ib<u<{
lb
(Round to five decimal places as needed.)
d. Write a brief statement that interprets the confidence interval. Choose the correct answer below.
OA. One has 90% confidence that the sample mean weight of Pepsi in a can is equal to the population
mean weight of Pepsi in a can.
OB. Approximately 90% of sample mean weights of Pepsi in a can will fall between the lower bound
and the upper bound.
OC. One has 90% confidence that the interval from the lower bound to the upper bound contains the
true value of the population mean weight of Pepsi in a can.
OD. There is a 90% chance that the true value of the population mean weight of Pepsi in a can will fall
between the lower bound and the upper bound.
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