Here are some data collected on a sample of cesium exposed to various energies of light. Light energy Electron emitted? Electron KE (eV) (eV) 2.12 2.13 2.14 2.15 2.16 no no yes yes yes - 0 0.01 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.
Here are some data collected on a sample of cesium exposed to various energies of light. Light energy Electron emitted? Electron KE (eV) (eV) 2.12 2.13 2.14 2.15 2.16 no no yes yes yes - 0 0.01 0.02 *Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
What is the threshold frequency ν0 of cesium?
Transcribed Image Text:Electrons are emitted from the surface of a metal
when it's exposed to light. This is called the
photoelectric effect. Each metal has a certain
threshold frequency of light, below which nothing
happens. Right at this threshold frequency, an
electron is emitted. Above this frequency, the
electron is emitted and the extra energy is
transferred to the electron.
The equation for this phenomenon is
KE= hv - hvo
-
where KE is the kinetic energy of the emitted
electron, h 6.63 × 10-34 J.s is Planck's
constant, is the frequency of the light, and vis
the threshold frequency of the metal.
Also, since E = hv, the equation can also be
written as
KE=E-O
where E is the energy of the light and is the
binding energy of the electron in the metal.
Transcribed Image Text:Here are some data collected on a sample of cesium exposed to various energies of light.
Light energy Electron emitted? Electron KE
(eV)
(eV)
2.12
2.13
2.14
2.15
2.16
no
no
yes
yes
yes
0
0.01
0.02
*Note that 1 eV (electron volt) = 1.60 × 10-¹⁹ J.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY